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Yuki888 [10]
3 years ago
7

Please Help!! 10 Points and Brainliest!!! WRONG ANSWERS WILL BE REPORTED.

Mathematics
2 answers:
dolphi86 [110]3 years ago
7 0

Answer: The answer is C, 39.

Keith_Richards [23]3 years ago
3 0

The answer is 39 hope its right

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nordsb [41]

Answer:

6 gallons = 3.785 liters

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PLs help me out what is 54 divied by 343
irga5000 [103]

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The answer is 0.157

Step-by-step explanation:

I hope it helps

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2 years ago
X + 5y =100<br> x +y = 60<br> Which ordered pair is the solution of the system?
Simora [160]

Answer:

lets start with the easy equation. X+Y=60. so we take 60 and subtract Y to get X by itself. meaning X = 60-Y. every time we see X replace with (60-Y).

X + 5Y = 100 change to

60-Y+5Y = 100

5Y - Y = 4y.

60+4Y = 100. 100 minus the 60 = 40. 4Y=40. divide by 4. Y = 10. ok so now we solve for X. X + Y (or 10) = 60. 60-10 = 50. X = 50.

Step-by-step explanation:

4 0
3 years ago
Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B220%20%2B%20221%7D%20" id="TexFormula1"
Ymorist [56]

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5 0
3 years ago
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If sin a= 12/13 and tan B 8/15 and angles a and b are in qundrant 1 find the value of tan (a+b)
natali 33 [55]

Answer:

The value of Tan (a + b) is \frac{-220}{21} .

Step-by-step explanation:

Given as :

Tan b = \frac{8}{15}

Sin a = \frac{12}{13}

∵Sin Ф = \dfrac{\textrm perpendicular}{\textrm Hypotenuse}

So,  \dfrac{\textrm perpendicular}{\textrm Hypotenuse} =  \frac{12}{13}

Now, Base² = Hypotenuse² -  Perpendicular²

Or, Base² = 13² - 12²

Or,  Base² = 169 - 144

Or,  Base² = 25

∴     Base = \sqrt{25} = 5

And Tan Ф =  \dfrac{\textrm perpendicular}{\textrm Base}

Or, Tan a = \frac{12}{5}

Now, Tan (a + b) = \dfrac{Tan a + Tan b}{1- Tan a Tanb}

Or, Tan (a + b) = \frac{\frac{12}{5}+\frac{8}{5}}{1-(\frac{12}{5}\times \frac{8}{15})}

or, Tan (a + b) = \frac{\frac{36+8}{15}}{\frac{75-96}{75}}

or, Tan (a + b) =\frac{\frac{44}{15}}{\frac{-21}{75}}

Or, Tan (a + b) = \frac{-220}{21}

Hence The value of Tan (a + b) is \frac{-220}{21} . Answer

5 0
3 years ago
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