Question

Please help me with this problem. I will give brainliest!

Answer 1

Answer:

centre = (11, 0 ), radius = 3

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - h)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

(x - 11)² + y² = 9 ← in standard form

with (h, k ) = (11, 0 ) and r² = 9 ⇒ r = $\sqrt{9}$ = 3

centre = (11, 0 ) and r = 3