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3 years ago

What is the value of y in this exponential growth function when x equals 3?

Mathematics

2 answers:

Reika [66]3 years ago

8 0

Y = 2(1.06)^x

y = 2(1.06)^3

y = 2(1.19)

y = 2.38

docker41 [41]3 years ago

7 0

Its hard to do the problem without the function or graph for the function but if you can get that i would love to help.

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How do you write y+1=4/5(x-3) in standard form?

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Answer:

The standard form of the given expression is $- (\frac{4}{5})x + y + (\frac{17}{5}) = 0$

Step-by-step explanation:

Here, the given expression is $y + 1 = \frac{4}{5} (x-3)$

Now, the Standard Form of the equation is ax + by + c = 0

Solving this, we get:

$y + 1 = \frac{4}{5} (x-3) \implies y + 1 = (\frac{4}{5})x - \frac{12}{5}$

⇒ $y + 1 - (\frac{4}{5})x + (\frac{12}{5}) = 0$

or, $y - (\frac{4}{5})x + (\frac{12}{5} + 1 )= 0 \implies y - (\frac{4}{5})x + (\frac{12+ 5}{5}) = 0$

⇒ $y - (\frac{4}{5})x + (\frac{17}{5}) = 0$

Hence, the standard form of the given expression is $- (\frac{4}{5})x + y + (\frac{17}{5}) = 0$

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