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3 years ago

Finding which number supports the idea that the rational numbers are dense in the real numbers.

Mathematics

1 answer:

aivan3 [116]3 years ago

8 0

Answer:A terminating decimal between -3.14 and -3.15.

Step-by-step explanation:

A natural number includes non-negative numbers like 5, 203, and 18476.

It is encapsulated by integers, which include negative numbers like -29, -4, and -198.

Integers are further encapsulated by rational numbers, which includes terminating decimals like 3.14, 1.495, and 9.47283.

By showing a terminating decimal between -3.14 and -3.15, you are showing that rational numbers include integers (because integers include negative numbers.

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I need help finding the area

aniked [119]

<h3>Given :</h3>

Base of triangle = 7 yd
Height of triangle = 10 yd

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Area of triangle

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We know:-

When base and height of triangle is given we use this formula:

$\bigstar \boxed{ \rm Area \: of \: triangle = \frac{base \times height}{2} }$

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So:-

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{base \times height}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 10}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times2 }{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times\cancel2 }{\cancel2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times1 }{1} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5$

$\\ \\$

$\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2} \\$

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$\therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^{ \red2} }}$

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$\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}$ ]

7 0

1 year ago

I need help with all of thies

levacccp [35]

Answer:

The equation for finding the hypotenuse is:

c^2+c^2=h^2

For example, in the first exercise:

8^2+10^2=164^2

For clearing the equation, find out the root of 164=

12.8

Hypotenuse of the first triangle is 12.8!

Let me help you with the next, if you still dont get it:

8^2+13^2=233^2

Root of 233: 15.2

Hypotenuse of second triangle is 15.2!

3 0

2 years ago

Noah wants to put $1,000 in a savings account with a 1.5% annual interest rate. How much more money will he have after one year

larisa86 [58]

Assuming that 1.5% annual interest is converted to monthly basis with the same amount, then the monthly interest should be: 1.5%/12= 0.125%.

If you put $1000 for annual interest, the saving account would become: $1000*(100%+1.5%)= $1015

If you put $1000 for monthly interest, the saving account would become: ($1000*(100%+0.125%)= $1000*1.0151035559= $1015.10

Then, the money difference should be: $1015.10-$1015= $0.10

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3 years ago