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Scrat [10]
3 years ago
10

A group of friends decided to buy a bulk of chocolate from a candy store if some friends each want 1 half of a kilogram of choco

late of 6 kilograms of chocolate purchased then how amny peoole can get a share of chocolate
Mathematics
1 answer:
notsponge [240]3 years ago
7 0
12 People would be able to have 1 half kilogram of chocolate. 
In order to solve this problem you have to multiply 6 by 2. There are two halves in a whole. 6 times 2 is equal to 12. 
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Elena-2011 [213]

Answer:

A.

Step-by-step explanation:

If

y=x^2+2x+7 AND

y = x + 7, then by the transitive property of equality:

x^2+2x+7=x+7

We can solve for the values of x by getting everything on one side of the equals sign and then solving for x:

x^2+x=0

We can factor out the common x to get:

x(x + 1) = 0

which tells us by the Zero Product Property that either

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We are expecting 2 solutions for x since this is a second degree polynomial.  We will sub both -1 and 0 into y = x + 7 to solve for the corresponding values of y

y = 0 + 7 so

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y = -1 + 7 so

y = 6 and the coordinate is (-1, 6)

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Answer:

(a)\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

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Step-by-step explanation:

Given the monthly profit model:

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We differentiate

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\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}

Simplifying

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}

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(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

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