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Novosadov [1.4K]
3 years ago
7

4. A rectangular park has been constructed in

Mathematics
1 answer:
Helga [31]3 years ago
3 0

Answer:

10ft

Step-by-step explanation:

Think of the rectangle as two right triangles. Sides a and b on the triangle are 8ft and 6 ft.  That's 8 squared + 6 squared = c squared.  C is 10 ft.

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GUYS PLEASE HELP WITH MY MWTH TEST
OleMash [197]

Answer:

sinθ = 5/13

cosθ = 12/13

tanθ = 5/12

Step-by-step explanation:

Get the remaining side(hypotenuse) first,

hypotenuse^2 = 12^2 + 5^2  (Pyth. theorem)

hypotenuse = 13

sinθ = 5/13

cosθ = 12/13

tanθ = 5/12

6 0
2 years ago
A lion runs at a speed of 50 mph and a cheetah runs 78 mph. If they both run at a steady rate, how far will a cheetah run in the
Elden [556K]

Answer:

21.45 mi

Step-by-step explanation:

Distance = speed × time

The time it takes the lion is:

13.75 mi = 50 mi/hr × t

t = 0.275 hr

The distance ran by the cheetah in that time is:

d = 78 mi/hr × 0.275 hr

d = 21.45 mi

7 0
3 years ago
Read 2 more answers
Which statement correctly compares the two functions shown?
krok68 [10]

Answer:

C.

Step-by-step explanation:

For Function 2

x=1 y=8

x=2 y=11

8=m+b

11=2m+b

11-8=2m-m

m=3

8=3+b

b=5

y=3x+5

Function 1

y=4x+5

Function 2

y=3x+5

....................

Function 1 has the same y-intercept and greater slope than Function 2.

4 0
2 years ago
The cost of labor for servicing cars at B&B Automotive is $50 for each whole hour or for any fraction of an hour. There is a
Masja [62]

Answer:

<h2>d. $250</h2>

Step-by-step explanation:

We can use the equation of a straight line to model the cost of servicing the car.

let the cost be y and the number of hours be x

and the charge per hour is m

y=mx+c

y=50x+25

given that the time is 3.45 hours it is assumed that the charge is for 4 hours since for a fraction of 0.45 hours we are charged $50

y=50(4)+25

y=200+25

y=$225

4 0
3 years ago
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 101010 denarii per day to support 444
givi [52]

<u>the correct question is</u>

The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?

Let

x-------> the cost to support a legionary per day

y-------> the cost to support an archer per day

we know that

4x+4y=10 ---------> equation 1

2x+2y=5 ---------> equation 2

If you multiply equation 1 by 2

2*(2x+2y)=2*5-----------> 4x+4y=10

so

equation 1 and equation 2 are the same

The system has infinite solutions-------> Is a consistent dependent system

therefore

<u>the answer is</u>

We cannot solve for a unique cost for each soldier, because there are infinite solutions.

5 0
3 years ago
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