What is the product? Two-thirds times eight-ninths StartFraction 10 over 27 EndFraction StartFraction 16 over 27 EndFraction Two
1 answer:
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Answer:
AC = 6.05 cm
Step-by-step explanation:
We can draw two different trapeziums with the information given.
The possible drawings of the trapezium ABCD are in the image attached.
In both trapeziums, the length of AC is the same, and we can calculate this length using the law of cosines in the triangle ABC:
AC^2 = AB^2 + BC^2 - 2 * AB * BC * cos(B)
AC^2 = 4.8^2 + 6.8^2 - 2 * 4.8 * 6.8 * cos(60)
AC^2 = 23.04 + 46.24 - 65.28 * 0.5
AC^2 = 36.64
AC = 6.05 cm
