Please I need help!! Thank you

The mean of a sequence of n numbers is m. If we split the sequence into two sequences of lengths n1 and n2 and compute their mea

Furkat [3]

The mean of a sequence of numbers is the average.

The true statement is: $\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}$

The given parameters are:

$\mathbf{Mean = m}$

$\mathbf{Size = n}$

The mean of a dataset is calculated as:

$\mathbf{Mean = \frac{\sum x}{Size}}$

So, we have:

$\mathbf{m = \frac{\sum x}{n}}$

Multiply both sides by m

$\mathbf{\sum x = mn}$

When the sequence is split into two, we have:

$\mathbf{\sum x_1 = m_1\times n_1}$

$\mathbf{\sum x_2 = m_2\times n_2}$

Where:

$\mathbf{\sum x_ = \sum x_1 + \sum x_2}$

So, we have:

$\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}$

Hence, the true statement is: $\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}$

Read more about mean and averages at:

brainly.com/question/16217700

8 0

3 years ago

HELPPP !!! ILL MARL BRAINLIST

almond37 [142]

Answer:

Hi there!

Your answers are:

1) 2^4 = 2×2×2×2 = 16

2) 2^3= 2×2×2= 8

3) 2^2 = 2×2 = 4

4) 2^1 = 2

5)2^0 = 1

6)2^ -1 = .5

7) 2^ -2 = .25

8) 2^ -3 = .125

9) 2^ -4= .0625

Hope this helps

3 0

3 years ago

A warehouse distributor of carpet faces a normally distributed demand for its carpet. The average demand for carpet from the sto

dimulka [17.4K]

Answer:

There is a 25.14% probability that the order will not be met during a month.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 4500, \sigma = 900$ .

The order will not be met if $X > 6000$ . So we find the pvalue of Z when $X = 6000$ , and subtract 1 by this value.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6000 - 4500}{900}$

$Z = 1.67$

$Z = 1.67$ has a pvalue of 0.7486.

So there is a 1 - 0.7486 = 0.2514 = 25.14% probability that the order will not be met during a month.

3 0

3 years ago

How Can a graph help you with the zero of a function?

Arturiano [62]

The zero of a function is the x-value where the function crosses the x-axis. With a graph, it is easier often to just look at where the function crosses the x-axis instead of calculating it mathematically.

4 0

3 years ago

Please help me i really really need help please please please help me

77julia77 [94]

I’m confused on what there is to help you with please be more specific

8 0

3 years ago