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Allushta [10]
2 years ago
8

Rachel tells Jonah that she can turn a square, but he won’t be able to tell that it was turned after she is finished turning it.

Mathematics
1 answer:
Dmitry [639]2 years ago
5 0
ANSWER: it’s a square. All sides will look the same after turning because all sides LOOK THE SAME lol.
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The measure of an angle exceeds 3 times its supplement by 4. Find the measure of the angles.
Dafna11 [192]
X=3y+4, y=y
x+y=180, 3y+4+y=180, 4y+4=180
4y+4=180
4y=176
y=44
x=3(44)+4, x=132+4, x=136

(I am not a very good artist in this case:)

4 0
2 years ago
Can someone help me I have two more other questions they are 15 points each I just posted them right now! Thanks so much
nlexa [21]

Answer:

$10 coins: 21

$20 coins: 24

Step-by-step explanation:

heyy me again

So we can create 2 equations where

x = number of $10 coins

y = number of $20 coins:

x + y = 45

10x + 20y = 690

we can move equation 1 around so that we can get a value of x

x = 45 - y

now we can substitute x into the second equation

10(45 - y) + 20y = 690

450 - 10y + 20y = 690

10y = 240

y = 24

Now plug in y back into the first equation

x = 45 - y

x = 45 - 24

x = 21

8 0
2 years ago
A painting is 6 in tall and 4 in wide. if it is reduced to a width of 2 in then how tall will it be?
Vlada [557]

6 inches squared is your answerStep-by-step explanation:4/2=2 6/2=3

3times 2 equals 6

8 0
2 years ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
2 years ago
Can you please help me understand this question please?
GREYUIT [131]

Answer:

B

u just subsitute in each inequality form and so u will find the only one that is right is letter b

-4 is x

-2 is y

5 0
2 years ago
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