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r-ruslan [8.4K]
3 years ago
6

If a 10-pound sack of potatoes costs $6.55, how much would 1 pound cost? Round your answer to the nearest cent. A. $.65 B. $.66

C. $1.65 D. $6.55
Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0
To determine the cost of 1 pound of potato, simply divide the 10-pound sack of potatoes cost by the number of pounds, 10. That is,
                               c = $6.55 / 10 = $0.655 
Thus, each pound of potatoes cost nearly $0.66. The answer is letter B. 
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If 12 pens are packed equally into 2 boxes, how many pens will each box hold?
bulgar [2K]

Answer:

6

Step-by-step explanation:

12/2=6

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8 0
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KiRa [710]

I've answered this before, but only partially. I'm not sure about the second part, but I think the first one is 10

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3 years ago
Find the common difference of the arithmetic sequence 13, 9, 5,...
stepan [7]

Answer:

it goes down by 4 every number

6 0
3 years ago
Select all the true statements. Triangle A B C where the measure of angle A is 2 x plus 1 degree, angle B is x degrees, and angl
Step2247 [10]

Answer:

B= 41; C  = 56; A = 83

Step-by-step explanation:

Given

A = 2x + 1

B = x

C = x + 15

Required

Arrange the angles from smallest to largest

First, we need to determine the value of x.

Since, it is a triangle:

A + B + C = 180

Substitute values for A, B and C

2x + 1+ x + x + 15 = 180

Collect Like Terms

2x + x + x = 180 - 15 -1

4x = 164

Solve for x

x= 164/4

x= 41

Solve for A, B and C

A = 2x + 1

A = 2 * 41 + 1

A = 82 + 1

A = 83

B = x

B= 41

C = x + 15

C  = 41 + 15

C  = 56

From Smallest to Largest, we have:

B= 41; C  = 56; A = 83

6 0
3 years ago
y = 3x + 3 y = x − 1 Explain how you will solve the pair of equations by substitution. Show all the steps and write the solution
Leona [35]
Y = 3x + 3
y = x - 1

As you can see, both equations are set to equal y. This means the right sides of each equation are equal, since y is isolated in both equations. So to solve this particular system of equations for x, set the right sides of both equations equal to each other. After you've done that, you can proceed to solve the equation algebraically for the variable, x.

3x + 3 = x - 1
2x + 3 = -1
2x = -4
x = -2

Negative two is the x-value. To find the y-value, substitute -2 for x into either equation and solve algebraically for y.

y = x - 1
y = -2 - 1
y = -3

The final step is to check all work by plugging both x- and y-values back into both equations.

y = 3x + 3
-3 = 3(-2) + 3
-3 = -6 + 3
-3 = -3  --  This is true

y = x - 1
-3 = -2 - 1
-3 = -3  --  This is true.

Answer:
(-2, -3)
5 0
3 years ago
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