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r-ruslan [8.4K]
2 years ago
6

If a 10-pound sack of potatoes costs $6.55, how much would 1 pound cost? Round your answer to the nearest cent. A. $.65 B. $.66

C. $1.65 D. $6.55
Mathematics
1 answer:
kolbaska11 [484]2 years ago
6 0
To determine the cost of 1 pound of potato, simply divide the 10-pound sack of potatoes cost by the number of pounds, 10. That is,
                               c = $6.55 / 10 = $0.655 
Thus, each pound of potatoes cost nearly $0.66. The answer is letter B. 
You might be interested in
Is (2, 2) a solution of y &lt; 4x - 6?<br> Choose 1 answer<br> yes or no
zalisa [80]

No, (2,2) is not solution of y < 4x - 6

Step-by-step explanation:

To solve above linear problem, we use standard method of  Back- Substitution.

First of all, A point (2,2) only becomes solution of equation, if it satisfies equation y < 4x - 6.

Here, the  y < 4x - 6  seems to be like a linear equation.

In this Equation, using  Back- Substitution method,

Point (2,2) : first digit 2 corresponds to x- coordinate and second digit 2 corresponds to y-coordinate.

           y < 4x - 6.....(1)     \\\         x= 2        .....(2)       \\\       y= 2        .....(3)

By putting value of x and y in equation (1),

Equation becomes,

        2 <  4 \times 2  - 6

       2 < 8       -  6

       2 <  2      .... not true mathematically.

Finally, the result came is not true. Therefore, (2,2) is not solution for equation

y < 4x - 6          

4 0
3 years ago
Please help!!! Find the equation for all 4!!! It needs to be <br> Y=mx +b
emmainna [20.7K]
1) y= 2/5x -3
2) y= 2/3x + 1
3) y= 2x -1
4) y= 5/4x + 3
I think
7 0
2 years ago
A bag of potatoes weighs about
ruslelena [56]
Bag of potatoes are usually 10 pounds
5 0
2 years ago
Mark made a scale drawing of a soccer field, using a scale of .5 cm=1m. The actual length of the field is 110 m. What is the len
VikaD [51]

Answer:

The length of the field on the drawing is <u>55 cm</u> that is option <u>D</u>.

Step-by-step explanation:

Given:

Mark made a scale drawing of a soccer field, using a scale of .5 cm=1 m.

The actual length of the field is 110 m.

Now, to find the length of the field on the drawing.

Let the length of the field on drawing be x\ cm.

As given,

Drawing of a soccer field, using a scale of 0.5 cm=1 m.

So, 0.5 cm is equivalent to 1 m.

Thus, x\ cm is equivalent to 110 m.

Now, to get the length of the field on the drawing by using cross multiplication:

\frac{0.5}{1} =\frac{x}{110}

By cross multiplying we get:

55=x

x=55\ cm

Therefore, the length of the field on the drawing is 55 cm that is option D.

7 0
3 years ago
(HELP ME 15 PTS)
kap26 [50]

Answer:   \bold{\dfrac{27x^2y^3}{16}}

<u>Step-by-step explanation:</u>

\dfrac{(3x^2y^5)^3}{(2xy^3)^4}\\\\\\=\dfrac{3^3\cdot x^{2\cdot 3}\cdot y^{5\cdot 3}}{2^4\cdot x^4\cdot y^{3\cdot 4}}\\\\\\=\dfrac{27\cdot x^6\cdot y^{15}}{16\cdot x^4\cdot y^{12}}\\\\\\=\dfrac{27\cdot x^{6-4}\cdot y^{15-12}}{16}\\\\\\=\dfrac{27\cdot x^2\cdot y^3}{16}

8 0
2 years ago
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