M<2 = m<3
but
m<1 + m<2 = 180
4x + 36 + <span>3x – 3 = 180
7x + 33 = 180
7x = 147
x = 21
m<2 = </span><span>3x – 3
m<2 = 3(21) - 3
m<2 = 63 - 3
m< 2 = 60
m<3 = m<2 = 60
answer
</span><span>60°</span>
Answer:
There are 8 tens and 2 ones
Step-by-step explanation:
Hope this helps
Answer:
i believe the answer is 9.5
Step-by-step explanation:
cos60 = c / 19 = 9.5
Answer:
<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>
Step-by-step explanation:
Givens
- Max has $5.50.
- He has eight more quarters than he does nickels.
- He had four times as many dimes as he has nickels.
From these statements, we can deduce algebraical expressions to solve the problem. Let's call
quarters,
nickels and
dimes.
(8 more quarters than nickels)
(he has four times as many dimes as he has nickels).
(Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).
Let's replace the first two expressions into the third equation
![0.25(n+8)+0.05n+0.10(4n)=5.50\\0.25n+2+0.05n+0.40n=5.50\\0.70n=5.50-2\\n=\frac{3.50}{0.70}\\ n=5](https://tex.z-dn.net/?f=0.25%28n%2B8%29%2B0.05n%2B0.10%284n%29%3D5.50%5C%5C0.25n%2B2%2B0.05n%2B0.40n%3D5.50%5C%5C0.70n%3D5.50-2%5C%5Cn%3D%5Cfrac%7B3.50%7D%7B0.70%7D%5C%5C%20n%3D5)
There are 5 nickels.
Now, we use this value to find the number of quarters
![q=5+8=13](https://tex.z-dn.net/?f=q%3D5%2B8%3D13)
There are 13 quarters.
Also, ![d=4(5)=20](https://tex.z-dn.net/?f=d%3D4%285%29%3D20)
There are 20 dimes.
Therefore, there are 13 quarters, 5 nickels and 20 dimes.