The sector (shaded segment + triangle) makes up 1/3 of the circle (which is evident from the fact that the labeled arc measures 120° and a full circle measures 360°). The circle has radius 96 cm, so its total area is π (96 cm)² = 9216π cm². The area of the sector is then 1/3 • 9216π cm² = 3072π cm².
The triangle is isosceles since two of its legs coincide with the radius of the circle, and the angle between these sides measures 120°, same as the arc it subtends. If b is the length of the third side in the triangle, then by the law of cosines
b² = 2 • (96 cm)² - 2 (96 cm)² cos(120°) ⇒ b = 96√3 cm
Call b the base of this triangle.
The vertex angle is 120°, so the other two angles have measure θ such that
120° + 2θ = 180°
since the interior angles of any triangle sum to 180°. Solve for θ :
2θ = 60°
θ = 30°
Draw an altitude for the triangle that connects the vertex to the base. This cuts the triangle into two smaller right triangles. Let h be the height of all these triangles. Using some trig, we find
tan(30°) = h / (b/2) ⇒ h = 48 cm
Then the area of the triangle is
1/2 bh = 1/2 • (96√3 cm) • (48 cm) = 2304√3 cm²
and the area of the shaded segment is the difference between the area of the sector and the area of the triangle:
3072π cm² - 2304√3 cm² ≈ 5660.3 cm²
Answer:
thanks lol
Step-by-step explanation:
Answer:
A= 37 degrees
C= 43 degrees
Step-by-step explanation:
Hey there!
So this question looks a lot more complicated than it really is.
Complementary angles are the same.
Supplementary angles add up to 180 degrees or in other words a straight line.
If A and B are complementary and B equals 37 degrees, than A is also 37 degrees.
To find C, all we would do is subtract 37 from 180 to find the leftover amount.
180-37=43
So, in conclusion:
A= 37 degrees
C= 43 degrees
Hoped this helped! :D
Comment if you have any further questions!
The 3 consecutive numbers are 41, 42, and 43 : 41+42+43= 126
