Let's do this by Briot-Ruffini
First: Find the monomial root
x - 2 = 0
x = 2
Second: Allign this root with all the other coeficients from equation
Equation = -3x³ - 2x² - x - 2
Coeficients = -3, -2, -1, -2
2 | -3 -2 -1 -2
Copy the first coeficient
2 | -3 -2 -1 -2
-3
Multiply him by the root and sum with the next coeficient
2.(-3) = -6
-6 + (-2) = -8
2 | -3 -2 -1 -2
-3 -8
Do the same
2.(-8) = -16
-16 + (-1) = -17
2 | -3 -2 -1 -2
-3 -8 -17
The same,
2.(-17) = -34
-34 + (-2) = -36
2 | -3 -2 -1 -2
-3 -8 -17 -36
Now you just need to put the "x" after all these numbers with one exponent less, see
2 | -3x³ - 2x² - 1x - 2
-3x² - 8x - 17 -36
You may be asking what exponent -36 should be, and I say:
None or the monomial. He's like the rest of this division, so you can say:
(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:
(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)
Just divide the rest by the monomial.
Answer:
Total overripe fruit = 48
Step-by-step explanation:
<em>Step 1: Assume the value of oranges</em>
Let oranges be x
Oranges = x
Apples = 32 + x
Overripe oranges = 3/5 of oranges
= 3x/5
Overripe apples = 1/3 of apples
= 1/3 (32 + x)
<em>Step 2: Find x (oranges)</em>
<em>Number of overripe apples and number or overripe oranges are equal.</em>
3x/5 = 1/3 (32 + x)
3 (3x) = 5(32 + x)
9x = 160 + 5x
4x = 160
x = 40
<em>Step 3: Find the total number of overripe fruit.</em>
Total overripe fruit = Overripe apples + Overripe oranges
Total overripe fruit = 1/3 (32 + x) + 3x/5
Total overripe fruit = 1/3 (32 + 40) + 3(40)/5
Total overripe fruit = 24 + 24
Total overripe fruit = 48
!!
<h3>
Answer: E) x^5</h3>
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Explanation:
We simply take half of the exponent 10 to get 5. This applies to square roots only.
So the rule is 
A more general rule is
![\sqrt[n]{a^b} = a^{b/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Eb%7D%20%3D%20a%5E%7Bb%2Fn%7D)
If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.
Is there any more to this question? Because-5 doesn’t belong anywhere
