I don’t understand how you worded the question but x=-4 if thats what you are looking for
Distance between two points P(x1,y1), Q(x2,y2):
D=sqrt((x2-x1)^2+(y2-y1)^2)
Polygons are generally named in order along the perimeter, so that for a rectangle ABCD, AC or BD are diagonals.
Here, we need the distance between points A(4,3) and C(-4,-2)
Applying the above formula for distance between two points,
D=sqrt((4-(-4))^2+(3-(-2))^2)=sqrt(8^2+5^2)=sqrt(64+25)=sqrt(89)
Answer:
The proposed equation is solved as follows:
2X + 7 = 21
2X = 21 - 7
2X = 14
X = 14 / 2
X = 7
The value of X is 7.
A first degree equation is an algebraic equation in which each term is either a constant or a product of a fixed term on a single variable. Therefore, this equation is a first degree one, since it only has a single variable, which is X.
Answer:
233.19 inch³
Step-by-step explanation:
Volume of prisms: Length * Width * Height
given for first prism: Length = 7 cm Width = 3.25 cm Height = 7 cm
given for second prism: length = 7 cm width = 3.25 height = 3.25
using the formula:
Total volume: prism 1 volume + prism 2 volume
Total volume: 7 * 3.25 * 7 + 7 * 3.25 * 3.25
: 159.25+ 79.9375
: 233.1875 inch³
: 233.19 inch³ .........rounded to nearest hundredth
C. x³-4x²-16x+24.
In order to solve this problem we have to use the product of the polynomials where each monomial of the first polynomial is multiplied by all the monomials that form the second polynomial. Afterwards, the similar monomials are added or subtracted.
Multiply the polynomials (x-6)(x²+2x-4)
Multiply eac monomial of the first polynomial by all the monimials of the second polynomial:
(x)(x²)+x(2x)-(x)(4) - (6)(x²) - (6)(2x) - (6)(-4)
x³+2x²-4x -6x²-12x+24
Ordering the similar monomials:
x³+(2x²-6x²)+(-4x - 12x)+24
Getting as result:
x³-4x²-16x+24
