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satela [25.4K]
3 years ago
13

¿Qué tipos de proteínas corresponden a la parte sólida del cuerpo y que porcentaje?

Chemistry
1 answer:
Nataly_w [17]3 years ago
8 0

Answer:

The solid parts are the bones or the bone / cartilage tissue of the body, where they are composed of proteins such as: collagen type 1 approximately 80%, in addition 10% of other proteins combined with polysaccharides such as osteonectin and bone sialoprotein, or others proteinglucan or glycoproteins.

Explanation:

These proteins are proteins that make up the bone tissue structure, forming part of the extracellular matrix, providing consistency and support.

Type 1 collagen is one of the most important proteins in hard tissues, since it is one of the first to be formed by the osteoblast during osteoid formation, which will later calcify and conform to mature bone.

The synthesis of type 1 collagen fundamentally requires vitamin C, and it is also synthesized initially in a reticular way when the bone is immature, and then linearly when the bone becomes laminar or mature.

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svetlana [45]

wrong. If its for the study island its potential energy only.

6 0
3 years ago
F 2.50 × 10−2 g of solid Fe(NO3)3 is added to 100. ML of a 1.0 × 10−4 M NaOH solution, will a precipitate form? (ksp=4 × 10−38 f
vladimir1956 [14]

Answer:

A precipitate will be formed

Explanation:

The Ksp equilibrium of Fe(OH)₃ is:

Fe(OH)₃ (s) ⇄ Fe³⁺(aq)+ 3OH⁻(aq)

And its expression is:

Ksp = 4x10⁻³⁸ = [Fe³⁺] [OH⁻]³

<em>Where the concentrations are concentrations in molarity in equilibrium,</em>

We can write Q as:

Q = [Fe³⁺] [OH⁻]³

<em>Where [] are actual concentrations in molarity of each specie.</em>

<em />

When Q>= Ksp; a precipitate is formed,

When Q< Ksp no precipitate is produced:

[OH⁻] = [NaOH] = 1.0x10⁻⁴M

[Fe²⁺] = 2.50x10⁻²g * (1mol / 179.85g) / 0.100L = 1.39x10⁻³M

<em>179.85g/mol is molar mass of Fe(NO₃)₂ and the volume of the solution is 0.100L = 100mL</em>

<em />

Q = [Fe³⁺] [OH⁻]³

Q = [ 1.39x10⁻³] [ 1.0x10⁻⁴]³

Q = 3.8x10⁻¹⁵

As Q >> Ksp; A precipitate will be formed

7 0
3 years ago
How many liters of water are needed to dissolve 75.0 grams of NaOH to prepare a 1.00-M solution?​
Pepsi [2]

Answer:

About 500

Explanation:

Bc i used my calc

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3 years ago
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Answer:

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n= mass/Molecular Weight

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n= 3,7mol

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M= 3,7mol/4L

M=0,925

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