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zmey [24]
3 years ago
8

What do the images embedded in rock represent?

Chemistry
1 answer:
xeze [42]3 years ago
7 0
You're correct It's D :))))))))<span />
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Determine the rate of a reaction that follows the rate law:
3241004551 [841]

Answer:

C

Explanation:

I am not 100% sure tho correct me if I'm wrong pls:/

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2 years ago
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Is crushing a rock a chemical or physical change?
aalyn [17]
Physical change because you didn't change the chemical compound 
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3 years ago
Part A Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide. Express your answer as a ch
Basile [38]

Answer:

2HNO3+Ca(OH)2 = Ca(NO3)2+2H2O

Explanation:

The reaction between Nitric acid(HNO3)and Calcium hydroxide(Ca(OH)2) gives Calcium Nitrate( Ca(NO3)2 and Water( H2O)

7 0
3 years ago
Type the correct answer in the box. Express your answer to three significant figures.
satela [25.4K]

Answer:

The partial pressure of argon in the jar is 0.944 kilopascal.

Explanation:

Step 1: Data given

Volume of the jar of air = 25.0 L

Number of moles argon = 0.0104 moles

Temperature = 273 K

Step 2: Calculate the pressure of argon with the ideal gas law

p*V = nRT

p = (nRT)/V

⇒ with n = the number of moles of argon = 0.0104 moles

⇒ with R = the gas constant = 0.0821 L*atm/mol*K

⇒ with T = the temperature = 273 K

⇒ with V = the volume of the jar = 25.0 L

p = (0.0104 * 0.0821 * 273)/25.0

p = 0.00932 atm

1 atm =101.3 kPa

0.00932 atm = 101.3 * 0.00932 = 0.944 kPa

The partial pressure of argon in the jar is 0.944 kilopascal.

5 0
3 years ago
A 2.950×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in w
11111nata11111 [884]

Answer:

The molality of the glycerol solution is 2.960×10^-2 mol/kg

Explanation:

Number of moles of glycerol = Molarity × volume of solution = 2.950×10^-2 M × 1 L = 2.950×10^-2 moles

Mass of water = density × volume = 0.9982 g/mL × 998.7 mL = 996.90 g = 996.90/1000 = 0.9969 kg

Molality = number of moles of glycerol/mass of water in kg = 2.950×10^-2/0.9969 = 2.960×10^-2 mol/kg

7 0
3 years ago
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