Question

The following reaction was carried out in a 2.50 LL reaction vessel at 1100 KK: C(s)+H2O(g)⇌CO(g)+H2(g)C(s)+H2O(g)⇌CO(g)+H2(g) If during the course of the reaction, the vessel is found to contain 10.0 molmol of CC, 16.0 molmol of H2OH2O, 3.30 molmol of COCO, and 7.00 molmol of H2H2, what is the reaction quotient QQQ? Enter the reaction quotient

Answer 1

Answer:

Q = 0.144

Explanation:

• C(s) + H2O(g) ↔ CO(g) + H2(g)

reaction quotient:

• Q = [H2(g)][CO(g)] / [H2O(g)][C(s)]

∴ [C(s)] = 10.0 mol/2.50 L = 4 M

∴ [H2O(g)] = 16.0 mol/2.50 L = 6.4 M

∴ [CO(g)] = 3.30 mol/2.50 L = 1.32 M

∴ [H2(g)] = 7.00 mol/2.50 L = 2.8 M

⇒ Q = (2.8 M)(1.32 M) / (6.4 M)(4 M)

⇒ Q = 0.144