Ok So From What You Said I Calculated This:
1:00-2:00
cars=c, trucks=t
answer=a
c x 3 = a
a÷3=t
Answer:
b||c; c||d; b||d
Step-by-step explanation:
Substituting 10 for x, in the angle beside b we have
7(10)-5 = 70-5 = 65
In the angle beside c we have
10(10)+15 = 100+15 = 115
In the angle beside d we have
12(10)-5 = 120-5 = 115
In the angle beside we have
8(10)-25 = 80-25 = 55
The angle beside c has a vertical angle on the other side of c. This angle would be same-side interior angles with the angle beside b; this is because they are inside the block of lines made by b and c and on the same side of a, the transversal. These two angles are supplementary; this is because 65+115 = 180. Since these angles are supplementary, this means that b||c.
The angle beside c and the angle beside d would be alternate interior angles; this is because they are inside the block of lines made by c and d and on opposite sides of the transversal. These two angles are congruent; this means that c||d.
Since b||c and c||d, by the transitive property, b||d.
It is the same thing as the average you add everything up then you divide by the number of numbers you added together
Answer:
a) 121 combinations
b) 124 combinations
Step-by-step explanation:
a) 5 possible number without repeating any will give us =
5 possible numbers* 4 possible numbers* 3 possible numbers* 2possible numbers + 1 possible numbers = 121 combination
b) 5 possible number but repeating 1 will give us 5 possible numbers* 4 possible numbers * 3 possible numbers* 2possible numbers
+4 possible number
124 combination
Answer:
Standard Error of the difference = 0.0695
Step-by-step explanation:
Its given that : In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport

Also, in the same district, 19 of 67 randomly selected high school juniors play a varsity sport

Now, finding the standard error of the difference :

Hence, Standard Error of the difference = 0.0695