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Anon25 [30]
3 years ago
9

So here is a theoretical question. Let L1 and L2 be linear transformation from a vector space V into Vector space W. Let {v1,v2,

....,vn} be a basis for V. Show that if L1(vi)=L2(vi) for i=1,2,....,n then L1(v)=L2(v) for any v in V. ...?
Mathematics
1 answer:
noname [10]3 years ago
6 0
<span>if v belongs to V, then we can find scalars a1,a2,...,an, such that v=a1*v1+a2*v2+...+an*vn, L1(v)=L1(a1*v1+a2*v2+...+an*vn) =a1*L1(v1)+a2*L1(v2)+...+an*L1(vn) =a1*L2(v1)+a2*L2(v2)+...+an*L2(vn) =L2(a1*v1+a2*v2+...+an*vn) =L2(v)</span>
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Answer:

-16 and -1

Step-by-step explanation:

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Let AB = 24, AC = 10 and BC = 26.
nata0808 [166]

Answer:

a) 24

b) 10

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d) 5/13

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Step-by-step explanation:

a) We can see that the leg opposite <C is AB, and we are given AB = 24

b) We can see the leg adjacent to <C is AC, and we are given that AC = 10

c) The trig function sine is equal to

\frac{opposite}{hypotenuse}

The opposite, AB, is 24, and the hypotenuse, BC, is 26. We can plug those numbers in:

sin(c) = \frac{24}{26} = \frac{12}{13}

d)The trig function cosine is equal to

\frac{adjacent}{hypotenuse}

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cos(c) = \frac{10}{26} = \frac{5}{13}

d)The trig function tangent is equal to

\frac{opposite}{adjacent}

The opposite, AB, is 24, and the adjacent, AC, is 10. We can plug those numbers in:

tan(c) = \frac{24}{10} = \frac{12}{5}

4 0
3 years ago
The triangles are similar. what is the value of x ?
jonny [76]

\dfrac{32}{4x+12}=\dfrac{8}{15}\\\\ \dfrac{8}{x+3}=\dfrac{8}{15}\\\\ x+3=15\\\\ x=12

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3 years ago
What is the gcf of 23 and 50
valkas [14]

Answer:

The greatest common factor of 23 and 50 is 1

Step-by-step explanation:

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