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3 years ago

Find the area of the circle round your answer to the nearest 10th

Mathematics

2 answers:

zhannawk [14.2K]3 years ago

6 0

Answer:

The area is 19.63.

Step-by-step explanation:

Alecsey [184]3 years ago

5 0

Step-by-step explanation:

Area of a circle is

$area = \pi \: r ^{2}$

area=3.14(2.5)²

19.63in²

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Andre says that any real number can go in either of the boxes and A will be a

Travka [436]

Answer:

Andy is incorrect

Step-by-step explanation:

[See attachment for complete question]

Andy is incorrect because of the following.

Filling the empty boxes with any real numbers does not guarantee that the expression will be a polynomial.

For instance, if the expression is completed as thus:

(5x⁴ + 4x³)(4x^(2.7981) - 6) = A

This expression is not a polynomial because all powers of x must be non negative and it must be an integer.

So, Andy's statement is incorrect

7 0

3 years ago

Balal rented a bicycle for 3 days while on vacation. He paid a fixed daily rate and a $32 damage deposit. The resulting cost was

svetoff [14.1K]

Answer: N=15

Step-by-step explanation:

3n+32=77

subtract 32 from 77 which you give you 45

3n=45 then divide it by three

so 45/3=15 so N=15

5 0

3 years ago

Please help me! Due soon!

givi [52]

Answer:

70/9

Step-by-step explanation:

We have the quadratic:

$3x^2+4x-9$

So, let’s find the roots of the quadratic. We will set the expression equal to 0:

$3x^2+4x-9=0$

Testing for factors, we can see that our quadratic isn’t factorable.

So, we can use the Quadratic Formula. The quadratic formula is given by:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case:

$a=3, b=4,\text{ and } c=-9$

Therefore, by substitution:

$\displaystyle x=\frac{-(4)\pm\sqrt{(4)^2-4(3)(-9)}}{2(3)}$

Evaluate:

$\displaystyle x=\frac{-4\pm\sqrt{124}}{6}$

Simplify the square root:

$\sqrt{124}=\sqrt{4\cdot31}=2\sqrt{31}$

Hence:

$\displaystyle x=\frac{-4\pm2\sqrt{31}}{6}$

Reduce:

$\displaystyle x=\frac{-2\pm\sqrt{31}}{3}$

So, our roots are:

$\displaystyle x_1=\frac{-2+\sqrt{31}}{3}, x_2=\frac{-2-\sqrt{31}}{3}$

We want to find the sum of the <em>squares</em> of our two roots. So, let’s square each term:

$\displaystyle (x_1)^2=\Big(\frac{-2+\sqrt{31}}{3}\Big)^2$

Square. For the numerator, we can use the perfect square trinomial patten where:

$(a+b)^2=(a^2+2ab+b^2)$

Therefore:

$\displaystyle (x_1)^2=\Big(\frac{(-2)^2+2(-2)(\sqrt{31})+(\sqrt{31})^2}{9}\Big)$

Simplify:

$\displaystyle (x_1)^2=\frac{35-4\sqrt{31}}{9}$

Similarly, for the second root, we will have:

$\displaystyle (x_2)^2=\Big(\frac{-2-\sqrt{31}}{3}\Big)^2$

So:

$\displaystyle (x_2)^2=\Big(\frac{(-2)^2+2(-2)(-\sqrt{31})+(-\sqrt{31})^2}{9}\Big)$

Simplify:

$\displaystyle (x_2)^2=\frac{35+4\sqrt{31}}{9}$

Therefore, our sum will be:

$\displaystyle (x_1)^2+(x_2)^2\\\\ \begin{aligned} &=\frac{35-4\sqrt{31}}{9}+\frac{35+4\sqrt{31}}{9}\\&=\frac{35-4\sqrt{31}+35+4\sqrt{31}}{9}\\&=\frac{70}{9}\end{aligned}$

Therefore, our final answer is 70/9.

3 0

3 years ago

What is the y-coordinate of the solution for the system of equations?

Snowcat [4.5K]

The answer is 14. y = 14 hope it helps.

8 0

3 years ago

Read 2 more answers

The question is in the picture

Andre45 [30]

Step-by-step explanation:

I hope I got it right.....

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below =)

3 0

3 years ago