Answer: 3.61×10^5 A
Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.
The formulae is given below as
B = u×Ia²/2(x²+a²)^3/2
Where B = strength of magnetic field on the axis of a circular loop = 4.15T
u = permeability of free space = 1.256×10^-6 mkg/s²A²
I = current on loop =?
a = radius of loop.
Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m
x = distance of the sensor away from center of loop = 2.10 cm = 0.021m
By substituting the parameters into the formulae, we have that
4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2
4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2
4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)
4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I
I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9
I = 4.80×10^-4 / 1.32665 ×10^-9
I = 3.61×10^5 A
False.
Right triangles do not have to be congruent.
:)
Answer:
Step-by-step explanation:
2x + 3.5x + 15 = -1.5
5.5x + 15 = -1.5
5.5x = -16.5
x = -3
y = 3.5(-3) + 15
= -10.5 + 15
= 4.5
(-3, 4.5)
Answer:
52b
Step-by-step explanation:
She has 52 cards per deck, and b decks.
This means she has 52b cards.
How this works:
For 1 deck, she has 52 cards, or 52×1 cards.
For 2 decks, she has 104 cards, or 52×1 cards.
For 5 decks, she has 260 cards, or 52×5 cards.
For 10 decks, she has 520 cards, or 52×10 cards.
Therefore, for b decks, she has 52×b, or 52b cards.
**This content involves writing algebraic expressions, which you may wish to revise. I'm always happy to help!
