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mart [117]
3 years ago
10

Help please ! I’m stuck

Mathematics
1 answer:
Troyanec [42]3 years ago
4 0
Y=1x-10 (sorry I could be wrong)
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A student has a bag of marbles. There are 75 blue marbles, 50 green marbles, 100 orange marbles, and 25 red marbles. They select
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Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The
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Answer:

C. H0 : p = 0.8 H 1 : p ≠ 0.8

The test is:_____.

c. two-tailed

The test statistic is:______p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

The p-value is:_____. 0.09887

Based on this we:_____.

B. Reject the null hypothesis.

Step-by-step explanation:

We formulate null and alternative hypotheses as  proportion of people who own cats is significantly different than 80%.

H0 : p = 0.8 H 1 : p ≠ 0.8

The alternative hypothesis H1 is that the 80% of the  proportion is different and null hypothesis is , it is same.

For a two tailed test for significance level = 0.2 we have critical value  ± 1.28.

We have alpha equal to 0.2  for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28

The test statistic is

p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

Where p = 0.8 , q = 1-p= 1-0.8= 0.2

n= 200

Putting the values

0.8 ± 1.28 \sqrt{\frac{0.8*0.2}{200} }

0.8 ± 0.03620

0.8362, 0.7638

As the calculated value of z lies within the critical region  we reject the null hypothesis.

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If 4 pound of sugar cost of 1 pound of sugar is and the cost of ten pounds of sugar is
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Ten pounds of sugar costs 2.5 pounds

Step-by-step explanation:

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