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3 years ago

How does the graph of g(x) = -5+2 compare to the graph of the parent function f(x) ==?

Mathematics

1 answer:

lys-0071 [83]3 years ago

6 0

Answer:

What ever the f(x) numbers are you just move -5 which is the x to the left. You move the +2 up from the y axis.

Step-by-step explanation:

Lets say I have (7,3) in the graph.

You count -5 from 7 which will be 2.

Then you count +2 from 3 which will be 5

The new dot or equation will be (2,5)

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2. Define any variables and tell the slope and y-intercept of the situation. Then, write an equation to represent

Otrada [13]

Answer:

x=number of hours

c(x)= 25x+75

y-intercept= (0, 75)

Equation= y=25x+75

Slope= 25

Step-by-step explanation:

75 would be the y intercept(constant) because that's the initial charge for a call.

25 would be the coefficient for x because the hour you spend on the call varies.

The slope is how steep the line is, in this case it is 25.

x is the number of hours because that is the time that varies.

3 0

3 years ago

Consider the diagram. Lines a and d are?

marta [7]

Answer:

perpendicular

Step-by-step explanation:

They form a 90 degree angle

5 0

3 years ago

A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo

never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that $\pi = 0.08$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a p-value of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}$

$0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}$

$\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2$

$n = 996.3$

Rounding up:

A sample of 997 is needed.

3 0

3 years ago

Fill in the blanks below to make a true statement. In a binomial experiment with n trials and probability of success p, if np (1

Sergeu [11.5K]

Answer:

$\mu_{x}=np$

$\sigma^2_{X}=np(1-p)$

Step-by-step explanation:

∵ When x is a random variable having distribution B(n, p), then for sufficiently large value of n, the following random variable has a standard normal distribution,

$\frac{x-\mu}{\sigma}\sim N(0,1)$