To find the height of the triangular prism, you will use he formula for finding the volume of a prism and solve for the missing height.
V = Bh, where B is the area of the base.
<u>126</u> = <u>63h</u>
63 63
h = 2 feet
The height of the triangular prism is 2 feet.
Answer:
b
Step-by-step explanation:
i just answered it
Answer:
side length each 5√2
Step-by-step explanation:
both legs have the same length, as the triangle is a 45 - 90 45
To find one side of the triangle us the cosine of an angle is equal to the ratio of the adjacent side to the hypotenuse.
cos(A)=adj/hyp
cos(A)=adj/10
adj=cos(A) * 10
adj = 5√2
Answer:
8
Step-by-step explanation:
<em>we have to follow PEDMAS.</em>
<u>what we have to do in each operation:</u>
Parenthesis ~ 100 + 8 to the second power
Exponents ~ 10 to the 2nd power, 8 to the 2nd power, 2 to the 3rd power
Multiplication ~ none
Division ~ 10 to the 2nd power - (100 + 8 to the second power) divided by 2 to the 3rd power
Addition ~ 100 + 8 to the 2nd power
Subtraction ~ 10 to the 2nd power - (100+8 to the second power)
<u>doing the work:</u>
we start with P: but in what we have to do in the Parenthesis, there is an exponent and addition. we do the exponent first. 8 to the second power is 64. now we can add. 100 + 64 = 164.
E: we did the 2nd exponent, but we need the other 2 for later. 10 to the 2nd power is 100, and 2 to the 3rd power is 8.
we can skip M because there isn't any multiplication to do.
D: we have to do 10 to the 2nd power - (100 + 8 to the second power) first. 100-164= 64. now we can devide. 64 devided by 8 = 8
A: we already did the addition in the parenthesis part.
S: we already did the addition in the parenthesis part.
Answer:
Probability of more than 9 adult Australian sheep dogs out of 12 weighing 65 lb or more
P(X > 9) = 0.00788
Step-by-step explanation:
The only assumption required for the question is that all 12 adult dogs sampled must all be Australian sheep dogs.
This is a binomial distribution problem
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of adult dogs to be sampled = 12
x = Number of successes required = number of dogs that weigh 65 lb or more
= more than 9; >9
p = probability of success = probability of a dog weighing 65 lb or more = 0.45
q = probability of failure = probability of a dog NOT weighing 65 lb or more = 1 - 0.45 = 0.55
P(X > 9) = P(X=10) + P(X=11) + P(X=12)
Solving each of these probabilities, using the binomial distribution formula
P(X = x) = ¹²Cₓ (0.45)ˣ (0.55)¹²⁻ˣ with x = 10, 11 and 12
P(X > 9) = P(X=10) + P(X=11) + P(X=12)
= 0.00679820806 + 0.00101130368 + 0.00006895252
= 0.00787846427
= 0.00788 to 3 s.f
Hope this Helps!!!
