J, K, and L are collinear
J is between K and L
LK = KJ + LJ
LK = 9x + 7
KJ = 2x - 3
LJ = 4x - 8
9x + 7 = (2x - 3) + (4x - 8)
9x + 7 = (2x + 4x) + (-3 - 8)
9x + 7 = 6x + -11
9x + 7 = 6x - 11
9x + 7 - 7 = 6x - 11 - 7
9x = 6x - 18
9x - 6x = 6x - 6x - 18
3x = -18
x = -6
∴ The value of x is -6
Answer:
A
Step-by-step explanation:
the formula of the slope is (y2 - y1)/(x2 - x1)
slope = (3-2)/(-1-2) = 1/(-3) = -1/3
First you plot in the y-intercept of the equation. To find the y-intercept, substitute 0 into x. -3m will cancel our giving you y=5. x=0, y=5, the first ordered pair is (0,5). Now after you plot in the y-intercept, use your slope, which is -3, to graph the points of the equation. Starting from (0,5), move down 3 spaces on the y-axis (because it’s -3) and you’ll end up at (0,2). Next move over 1 ( all slopes with just a whole number moves on the x-axis 1 since the whole number divided by 1 doesn’t change the slope number) to the right because it’s a negative linear equation so it’ll go downward. After moving right, you’ll get (1,2). Do a couple more points starting from (1,2) then the 3rd point ABD and so on to get 3 or more points to be able to draw a linear line.
Answer:
0.3
Step-by-step explanation:
Find the number in the tenth place
3
and look one place to the right for the rounding digit
1
. Round up if this number is greater than or equal to
5
and round down if it is less than
5
.
0.3
