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3 years ago

Picture attached, please simplify

Mathematics

2 answers:

Varvara68 [4.7K]3 years ago

6 0

The 3th one

Step by step explanation

gavmur [86]3 years ago

4 0

Answer: the third choice.

Step-by-step explanation:

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If f(x)=3x^2 and g(x)=4x^3, what is the degree of (f*g)(x)?

Westkost [7]

3x^2 * 4x^3 = 12x^5

Answer is degree 5

3 0

3 years ago

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Find the solutions to the system of equations. Select all that apply. Y=x^2-1 y=2x-2

Sliva [168]

Answer:

Option C (1, 0)

Step-by-step explanation:

We have a system with the following equations:

$y = x ^ 2-1\\\\y = 2x-2$

The first equation is a parabola.

The second equation is a straight line

To solve the system, substitute the second equation in the first and solve for x.

$2x-2 = x ^ 2 -1$

Simplify

$x ^ 2-2x + 1 = 0$

You must search for two numbers that when you add them, obtain as a result -2 and multiplying both results in 1.

These numbers are -1 and -1

Therefore

$x ^ 2-2x + 1= (x-1)(x-1)\\\\x ^ 2-2x + 1= (x-1)^2=0$

Finally the solutions are

$x = 1\\y =0$

8 0

3 years ago

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If I want to buy a pair of sunglasses and the original price is $120, how much will I pay if they are 50% off? What if they were

gogolik [260]

Answer:

$60, $90

Step-by-step explanation:

Amount paid when 50% off

=$ 120 - 50/100 * 120 = $ 120 - $60 = $60

Amount paid when 25% off

=$ 120 - 25/100 * 120 = $ 120 - $30 = $90

4 0

3 years ago

100 pts help me please.

Natalija [7]

Answer:

Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.

Step-by-step explanation:

We know that:

48 + 8(b) = Carly's expenditure
10(b) = Carly's expenditure
48 + 8b = 10b
B = Boxes of cards

Work:

48 + 8b = 10b
=> 48 + 8b - 8b = 10b - 8b
=> 48 = 2b
=> b = 24

Now, let's substitute the value of b into any equation.

10(24)
=> 240

Hence, Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.

Hoped this helped.

$BrainiacUser1357$

7 0

2 years ago

Rewrite the rational exponent as a radical by extending the properties of integer exponents.

Aloiza [94]

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\\\ \textit{also recall that }a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} \qquad \qquad \sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}} \\\\ -------------------------------$

$\bf \cfrac{11^{\frac{2}{5}}}{11^{\frac{1}{4}}}\implies 11^{\frac{2}{5}}\cdot 11^{-\frac{1}{4}}\implies 11^{\frac{2}{5}-\frac{1}{4}}\implies 11^{\frac{8-5}{20}}\implies 11^{\frac{3}{20}} \\\\\\ \sqrt[20]{11^3}\implies \sqrt[20]{1331}$

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3 years ago

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