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xz_007 [3.2K]
3 years ago
7

Picture attached, please simplify

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
6 0
The 3th one





Step by step explanation
gavmur [86]3 years ago
4 0

Answer: the third choice.

Step-by-step explanation:

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nadya68 [22]

Answer:

<u>Right</u><u> </u><u>option</u><u> </u><u>is</u><u> </u><u>B</u><u>.</u><u> </u>

Step-by-step explanation:

\sf  \longrightarrow \frac{ \sec x \sin( - x)  +  \tan( - x) }{1 +  \sec( - x) }  \\  \\  \sf \longrightarrow  \frac{ \sec x( -  \sin x) -  \tan x}{1 +  \sec x}  \\  \\  \sf  \longrightarrow   \frac{  - \frac{1}{ \cos x } \times  \sin x -  \tan x }{1 +  \sec x}  \\  \\  \sf  \longrightarrow \frac{ -  \tan x -  \tan x}{1 +  \sec x}   \\  \\  \sf  \longrightarrow  \frac{ - 2 \tan x}{1 +  \sec x}  \\  \\  \sf \longrightarrow   \frac{  \frac{ - 2 \sin x}{ \cos x} }{1 +  \frac{1}{ \cos x} }  \\  \\  \sf  \longrightarrow  \frac{  \frac{ - 2 \sin x}{ \cos x} }{ \frac{ \cos x + 1}{ \cos x} }  \\  \\     \boxed{  \sf{\longrightarrow \frac{ - 2 \sin x}{ \cos x + 1}  }}

4 0
1 year ago
Which of the following is an extraneous solution of the square root of -3x-2=x+2
yarga [219]

Answer:

x=-6 is an extraneous solution

Step-by-step explanation:

we have

\sqrt{-3x-2} =x+2

squared both sides

-3x-2=(x+2)^2

-3x-2=x^2+4x+4

x^2+7x+6=0

solve the quadratic equation by graphing

The solution is x=-6 and x=-1

see the attached figure

<u><em>Verify each solution</em></u>

substitute the value of x in the original expression

For x=-6

\sqrt{-3(-6)-2} =-6+2

\sqrt{16} =-4

4=-4 ----> is not true

so

Is an extraneous solution

For x=-1

\sqrt{-3(-1)-2} =-1+2

\sqrt{1} =1

1=1 ----> is true

so

Is the solution

4 0
3 years ago
Melissa has enough paint to cover an area of 250 square feet.she want to paint two walls.the rectangular wall is 9 feet high and
liraira [26]

Answer:

No she doesn't have enough paint.

Step-by-step explanation:

You have to find the area of both walls then subtract both areas by 250. It would give you a negative number, meaning there is not enough paint.

5 0
2 years ago
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PLEASE HELP ME!!!!! A quadrilateral with vertices (0,0), (4,0), (3,2), (1,1) is mapped to a quadrilateral with vertices (6,3).(-
Murljashka [212]

Answer:

( 2,1) is the center of dilation and -2 is the scale factor

Step-by-step explanation:

We can use the formula

A' = k( x-a) +a, k( y-b)+b  where ( a,b) is the center of dilation and k is the scale factor

(0,0) becomes (6,3)

( 6,3) =  k( 0-a) +a, k( 0-b)+b

6 = -ka+a

3 = -kb+b

We also have

(4,0) becomes (-2,3)

( -2,3) =  k( 4-a) +a, k( 0-b)+b

-2 =4k -ka+a

3 = -kb+b

Using these two equations

6 = -ka+a

-2 =4k -ka+a

Subtracting the top from the bottom

-2 =4k -ka+a

-6 = ka -a

-------------------

-8 = 4k

Divide by 4

-8/4 = 4k/4

-2 = k

Now solving for a

6 = -ka +a

6 = - (-2)a +a

6 = 2a+a

6 = 3a

Divide by 3

6/3 =3a/3

2=a

Now finding b

3 = -kb+b

3 = -(-2)b+b

3 = 2b+b

3 = 3b

b=1

6 0
3 years ago
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Answer:

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