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Lina20 [59]
3 years ago
8

Could someone help me find the x and y

Mathematics
1 answer:
Maslowich3 years ago
5 0
This triangle is a 45 - 45 - 90 triangle, making it an isosceles triangle. So, x is 13. In every isosceles right triangle, the hypotenuse is the length of each leg times the square root of 2. So, y is 13 times the square root of 2
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Whats the solution of <br> y = x +2 <br> 2x - 5y = 2
aleksandr82 [10.1K]

Answer:

x = -4, y = -2

Step-by-step explanation:

substitute for y

2x - 5(x + 2) = 2

distribute -5

2x -5x - 10 = 2

solve

-3x - 10 = 2

add 10 on both sides

-3x = 12

divide by -3

x = -4

now substitute for x in the equation y = x + 2

y = -4 + 2

y = -2

7 0
3 years ago
Here is a list of numbers
skelet666 [1.2K]

Answer:

45 and 16 because:45 - 16 = 29

7 0
4 years ago
Keisha has a straightedge and a compass, but no protactor. what kind of angle can Keisha drag exactly with only these two tools?
nekit [7.7K]
A 90˚ angle
a 180 angle
6 0
4 years ago
In ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. Find the measure of ∠J to the nearest degree.
nydimaria [60]

We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.

First of all, we will draw a triangle as shown in the attachment.

We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.

We know that sine relates opposite side of right triangle to hypotenuse.

\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}

\text{sin}(\angle J)=\frac{22}{54}

Using inverse sine or arcsin, we will get:

\angle J=\text{sin}^{-1}(\frac{22}{54})

\angle J=24.042075905756^{\circ}

Upon rounding to nearest degree, we will get:

\angle J\approx 24^{\circ}

Therefore, the measure of angle J is approximately 24 degrees.

8 0
4 years ago
( 7x + 2x - 3x2 + 9x) + (5x + 8x2 - 6x2 + 2x - 5)​
Elena-2011 [213]

Answer:

-x2+25x-5

Step-by-step explanation:

7x+2x−3x2+9x+5x+8x2−6x2+2x−5

=−x2+25x−5

3 0
3 years ago
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