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Sonbull [250]
3 years ago
15

Find x and y Need done before 11:59

Mathematics
2 answers:
katen-ka-za [31]3 years ago
6 0

Answer:

Step-by-step explanation:

(3x + 6)° = 78°

3x = 72°

x = 24°

z = 180° - 78° = 102°

padilas [110]3 years ago
4 0

Answer:

x= 102

z= 24

Hope it will help you :)

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How do I create a radical equation with an extraneous solution quickly? How do I go the same for a radical equation with a non-e
Step2247 [10]

Answer:

why r u wafflin

Step-by-step explanation:

5 0
3 years ago
Last year the 6th grade had 350 students.This year the number decreased 36%.How many students are in this years 6th grade class
denis-greek [22]
The decrease in students are <span>350⋅0.36=126</span>
The number of students are <span>350−126=224</span> in this year.[Ans]The number of students are 224 <span>in this year.
https://socratic.org/questions/last-year-the-6th-grade-had-350-students-this-year-the-number-decreas...
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4 0
3 years ago
Read 2 more answers
A circular field has a area of 14400 sq ft <br> What is the diameter of the field?
Bingel [31]

Answer:

240/sqrt(pi)

Step-by-step explanation:

We know that the area of a circle is $pi*r^2$, and we also know that the diameter of a circle is equal to $2r$.

Let's first make an equation for this problem.

pi*r^2=14400

Dividing both sides by pi, we get

r^2=14400/pi

Now, taking the square root of both sides gives us

r=120/sqrt(pi)

We are trying to find the diameter, which is twice the size of the radius.

Thus, we multiply the equation by two.

2r=240/sqrt(pi)

6 0
3 years ago
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
Please help me on this math question?
Whitepunk [10]
M=30° because the right angle and 60 degree angle equal 150 and 180 (degrees in a triangle) minus 150 is 30

n=50° because 40 plus the right angle is 130 then the difference between that and 180 is 50 then n is the vertex angle of the one you found

t=98° because answer n plus the other part to the straight angle including the 112° angle is 68 then the total angle turns to 118 then the final angle turns to 62 via earlier reasoning, then because of another straight angle t=98

use the earlier reasoning to fine the other answers of

p=71°
q=39°

use the angle degrees formula to get Pentagon's maximum angles then use earlier resources

the final answers u should be able to figure out from there and u will never learn unless you do some yourself
5 0
3 years ago
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