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Pavel [41]
2 years ago
8

Did I do this right? If pls tell me how to fix it. Pls, look at the attachment.

Mathematics
1 answer:
anastassius [24]2 years ago
7 0
It looks all good to me! :) gj
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Whats -2(x-3)=5(2x+3)
puteri [66]
-2(x - 3) = 5(2x + 3)

-2x + 6 = 10x + 15

6 = 10x + 15 + 2

6 = 12x + 15

6 - 15 = 12x

-9 = 12x

-9/12 = x

-3/4 = x     or in decimal form; -0.75

hope this helps, God bless!
8 0
3 years ago
Read 2 more answers
How is. X^2=36 rational?
elena55 [62]

Answer:

{x}^{2}  = 36 \\ x =  \sqrt{36 } \\ x = 6 \\ it \: is \: rational \: number \: because \: we \: can \: write \: 6as \: 6 \1 \: it \: is \: in \: the \: form \: of \: p  \q \: where \:  \: q \: i \: not \: equals \: to \: 0

hope this will help you.

6 0
3 years ago
Which rule describes the composition of transformations that maps pre-image ABCD to final image A"B"C"D"? Reflection across the
svetlana [45]

Answer:

A on edge 2020

Step-by-step explanation:

6 0
3 years ago
Which equation shows a valid step in solving /2x-6+2x+6=0?
AfilCa [17]

An equation which shows a valid step that can be used to solve the given mathematical equation is (\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3

<h3>What is an equation?</h3>

An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.

In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.

Take the cube of both sides, we have:

\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3

Read more on equations here: brainly.com/question/13170908

#SPJ1

5 0
2 years ago
The area of a rectangle is 60 cm2 If the width of the
aleksklad [387]

The length of the rectangle is 10 cm and perimeter of the rectangle is 32 cm.

Step-by-step explanation:

Given,

The area of rectangle = 60 sq cm

Width (b) of the rectangle = 6 cm

To find the length and perimeter of the rectangle.

Formula

The area of the rectangle = l×b

The perimeter of the rectangle = 2(l+b)

According to the problem,

l×b = 60

or, l×6 = 60

or, l = 60÷6 = 10

Length (l) = 10 cm

Perimeter = 2×(10+6) cm = 32 cm

6 0
3 years ago
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