-2(x - 3) = 5(2x + 3)
-2x + 6 = 10x + 15
6 = 10x + 15 + 2
6 = 12x + 15
6 - 15 = 12x
-9 = 12x
-9/12 = x
-3/4 = x or in decimal form; -0.75
hope this helps, God bless!
An equation which shows a valid step that can be used to solve the given mathematical equation is ![(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B2x%20-%206%7D%29%5E3%20%3D%20%28-%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%29%5E3)
<h3>What is an equation?</h3>
An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.
In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.
Take the cube of both sides, we have:
![\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%20-%206%7D%20%2B%20%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%20%3D%200%5C%5C%5C%5C%28%5Csqrt%5B3%5D%7B2x%20-%206%7D%29%5E3%20%2B%20%28%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%29%5E3%20%3D%200%5E3%5C%5C%5C%5C%28%5Csqrt%5B3%5D%7B2x%20-%206%7D%29%5E3%20%3D%20%28-%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%29%5E3)
Read more on equations here: brainly.com/question/13170908
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The length of the rectangle is 10 cm and perimeter of the rectangle is 32 cm.
Step-by-step explanation:
Given,
The area of rectangle = 60 sq cm
Width (b) of the rectangle = 6 cm
To find the length and perimeter of the rectangle.
Formula
The area of the rectangle = l×b
The perimeter of the rectangle = 2(l+b)
According to the problem,
l×b = 60
or, l×6 = 60
or, l = 60÷6 = 10
Length (l) = 10 cm
Perimeter = 2×(10+6) cm = 32 cm