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aniked [119]
3 years ago
12

Which of the following is a polynomial function in factored form with zeros at -6,-2,and 3?

Mathematics
2 answers:
exis [7]3 years ago
8 0
The first one is the good one.
IRINA_888 [86]3 years ago
6 0

Answer:

A. f(x)=(x+6)(x+2)(x-3)

Step-by-step explanation:

The zeros or roots of a function are the numbers that when they are entered into the function the output will be 0.

We will evaluate the given numbers (-6,-2,3)to see in wich option all of them wil give us 0 in the output, Let´s start with the first option A) as follows:

f(-6)=((-6)+6)((-6)+2)((-6)-3)=(0)(-4)(-9)=0

f(-2)=((-2)+6)((-2)+2)((-2)-3)=(4)(0)(-5)=0

f(3)=((3)+6)((3)+2)((3)-3)=(9)(5)(0)=0

As we can see this is the correct option in which all of the values give us the output 0 adn we dont need to evaluate the resto of the options (B), C) and D))

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9x6+3=57
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A soma de três númerosemanas é 8470. O primeiro é 4319 e o segundo é 1843. Determine o terceiro número
Mice21 [21]

A soma de 3 numeros igual a 8470 seria:

X + Y + Z = 8470

Como é dito que o 1º é 4319 e o 2º 1843, entao

X + Y + Z = 8470

4319 + 1843 + Z = 8470

Z = 8470 - 4319 - 1843

<h3>Z = 2308</h3>
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3 years ago
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mafiozo [28]
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5 0
3 years ago
g natasha is in a class of 30 students that selects 4 leaders. How many ways are there to select the 4 leaders so that natasha i
Papessa [141]

Answer:

<h2>3,654 different ways.</h2>

Step-by-step explanation:

If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).

Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.

nCr = n!/(n-r)!r!

Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.

29C3 = 29!/(29-3)!3!

29C3 = 29!/(26!)!3!

29C3 = 29*28*27*26!/26!3*2

29C3 = 29*28*27/6

29C3 = 3,654 different ways.

This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders

5 0
3 years ago
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