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3 years ago

17(6+k)>3(5k+4) Inequalities

2 answers:

4 0

17(k + 6) > 3(5k + 4)
17(k) + 17(6) > 3(5k) + 3(4)
17k + 102 > 15k + 12
- 17k - 15k
2k + 102 > 12
- 102 - 102
2k > -90
2 2
k > -45

Mademuasel [1]3 years ago

3 0

-40<k, i think this is it. little rusty on inequalities

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To the nearest tenth the value of x that satisfies 2x = −2x + 11 is

Anuta_ua [19.1K]

To solve for variable equations or inequalities, we want to do two things:
1. Reduce one side to variables only
2. Reduce that side to the variable without coefficients.

The given equation is $2x=-2x+11$ .

Let's perform step 1: reducing one side to variables only. By adding $2x$ to both sides of the equation, we get $4x=11$ .

Now let's perform step 2: reducing that side to the variable without coefficients. Since the coefficient of $4x$ is $4$ , we need to divide both sides of the equation by 4: $x=\frac{11}{4}=2.75$ . Rounded to the nearest tenth, $x=2.8$ .

So the value of $x$ that satisfies $2x=-2x+11$ is $x=2.8$ .

4 0

3 years ago

-8x+3(x-5)=25 solve for x<br><br> literally i will give u points or whatever just get me an answer

Nana76 [90]

Answer:

x = -8

Step-by-step explanation:

-8x + 3(x - 5) = 25

Distribute the 3 into the (x - 5).

-8x + 3x - 15 = 25

Combine like terms.

-5x - 15 = 25

Add 15 to both sides.

-5x = 40

Divide both sides by -5.

x = -8.

Proof:

-8x + 3(x - 5) = 25

Substitute variable.

-8(-8) + 3((-8) - 5) = 25

Subtract inside parenthesis.

-8(-8) + 3(-13) = 25

Multiply -8 and -8.

64 + 3(-13) = 25

Multiply 3 and -13.

64 + (-39) = 25

Add 64 and -39.

25 = 25

4 0

2 years ago

Read 2 more answers

(a) How many integers in the range 1 through 120 are integer multiples of 2, 3, or 5? keyboard_arrow_down Solution (b) How many

Umnica [9.8K]

Answer:

(a) 88 integers

(b) 92 integers

Step-by-step explanation:

(a) integers whose last digits are divisible by 2 are multiples of two or numbers whose digits ends with zero. So for number 1-120 , all the even numbers which are sixty in number are are multiples of two.

For 3, numbers whose digits sum is divisible by three are multiples of three. 3,6,9,12,15,18,21,24,27,30 are multiples of three from numbers 1-30. we have four 30s in 120. which means numbers of integers will be 10*4 = 40integers. However out of these numbers , half are also integers of 2 which reduces the number added to 20integers.

For 5, numbers whose digits ends with 5 or 0 are multiples of 5. this gives us 24 integers for 1-120. but out of these 24integers, 16 are common integers of 2 and 3 which reduces the number added to 8integers.

Thus from 1-120 the intergers of 2,3 or 5 = 60+20+8 = 88integers.

(b) if we are considering from numbers 1-140;

for 2 we wil have 70 integers,

for 5 we will have 28 integers, but those integers that end with 0 are also integers of 2 which reduces the number added to 14.

For 7, numbers 7,14,21,28,35,42,49,56,63,70 are multiples of three from 1-70. This pattern is repeated from number 71-140. hence we have 20 integers in all. However 12 of the multiples are also multiples of either 2 or 5 which reduces the number to 8 integers.

Thus from 1-140, the integers of 2, 5, or 7 = 70+14+8 = 92integers

3 0

3 years ago

Hey I need help The radius of a circle is 8 cm. Find its area in terms of π

saveliy_v [14]

Answer:

≈201.06193

Step-by-step explanation:

A = πr2=(π)82

≈201.06193

7 0

3 years ago

The points (4, 9) and (0, 0) fall on a particular line. What is its equation in slope-intercept form?

Nikolay [14]

Answer:

The equation of the line would be y = 4/9x

Step-by-step explanation:

In order to find the equation, we first need to find the slope. We can do this by using the slope equation with the points.

m(slope) = (y2 - y1)/(x2 - x1)

m = (9 - 0)/(4 - 0)

m = 9/4

Now that we have this, we can use point-slope form along with one of the points to get the equation.

y - y1 = m(x -x1)

y - 0 = 4/9(x - 0)

y = 4/9x

5 0

3 years ago