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2 years ago

Distance between (-6,8) and (-3,9)

Mathematics

1 answer:

Mademuasel [1]2 years ago

7 0

Answer:

$\sqrt{10}$

Step-by-step explanation:

Using the distance formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

substitute

$d = \sqrt{((-3) - (-6))^2 + ((9)-(8))^2}$

$\sqrt{10}$

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Find the surface area of the cube (5.1cm tall)

joja [24]

Answer:

156.06cm

Step-by-step explanation:

sa=LW6

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3 years ago

Read 2 more answers

1<br> What is the solution to the equation 5x + 4 =19

ivolga24 [154]

Answer:

x=3

Step-by-step explanation:

5x + 4 = 19

-4 -4

5x = 15

/5 /5

x = 3

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2 years ago

Marcus works at a clothing store and gets an employee discount. The price

dybincka [34]

9514 1404 393

Answer:

d(32) = 28.80

the price Marcus pays on an item with an original price of 32

Step-by-step explanation:

d(32) = 32 -0.1(32)

d(32) = 28.8

The problem statement tells you d(32) is the price Marcus pays when the original price is 32.

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1 year ago

A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2, drawn from the 11, will

svet-max [94.6K]

The required probability is $\frac{36}{55}$

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, $\text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}$

Probability for first draw to be non-defective $=\frac{11-2}{11}=\frac{9}{11}$

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective $=\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}$

(printers after first slot = 10; total defective printers = 2)

Then, total probability $=\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}$

7 0

3 years ago

Find the slope of the line passing through the two points.

pogonyaev

Formula for slope: y2-y1/x2-x1
Plug in values.
3-8/-4-(-7)= -5/3 = slope
42-1/36-12=41/24=slope

6 0

3 years ago