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2 years ago

Distance between (-6,8) and (-3,9)

Mathematics

1 answer:

Mademuasel [1]2 years ago

7 0

Answer:

$\sqrt{10}$

Step-by-step explanation:

Using the distance formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

substitute

$d = \sqrt{((-3) - (-6))^2 + ((9)-(8))^2}$

$\sqrt{10}$

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19.60 +4.31 ——— these are decimals

professor190 [17]

Answer:

23.91

Step-by-step explanation:

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2 years ago

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Find the area of this figure! (Don’t give me a big explanation, i have 30 mins to get this ixl to 90, currently at 74)

Evgen [1.6K]

315 m²

area of rec + area of rec + area of rec + area of triangle

⇒ length + width + length + width + length + width + 1/2 * base * height

⇒ 19 * 6 + 9 * 9 + 18 * 5 + 1/2 * 12 * 5

⇒ 90 + 30 + 81 + 114

⇒ 315 m²

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1 year ago

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Amanda is making pastry dough. She mixes of a 1/3cup of flour and of a 1/5 cup of sugar. If she wants to mix flour and sugar in

mr_godi [17]

Flour : sugar = (1/3) : (1/5) = 5 : 3 . . . . . . . . multiply the first ratio by 15 to eliminate fractions

The total of ratio units in the last representation is 5+3=8, so for a recipe of 16 cups, each ratio unit will stand for 16/8 = 2 cups.

Multiplying the ratio by 2 cups, we find Amanda will need

... 10 cups flour : 6 cups sugar

for her recipe.

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3 years ago

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-4^6•4^2/4^4 Simplify

elena-14-01-66 [18.8K]

Answer:

$-4^{4}$

Step-by-step explanation:

Reduce the expression -4^2×4^2

Calcualte the product and you get -4^4

If you want the alternative form is will be -256

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2 years ago

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago