We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
The coefficient represents how many quarters it is
Answer:
17
Step-by-step explanation:
Look at any 2 adjacent numbers and find the difference between them.
Starting with numbers 1 and 2, subtract the first from the second:

That's a difference of 8, meaning the second number increased by 8.
Check the next numbers, 2 and 3:

It increased by 8 again. Now that we know for sure that each term in the sequence increases by 8 over the previous one, we can find the number in the green box. Just add 8 to the number before it:
