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Natalija [7]
3 years ago
6

A vertex of a secant-tangent angle is a point on the circle. a. always c. never b. sometimes

Mathematics
1 answer:
zavuch27 [327]3 years ago
4 0
Your answer is Sometimes because <span> A </span>secant<span> passes through a </span>circle<span> at two </span>points, a tangent<span> at one.

Hope this helps :)
If you need more help in future let me know :D</span>
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Find the quotient. 8,489÷9
eimsori [14]
The answer is 943.2.
4 0
3 years ago
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(9 – 23) + |47 – 16|
laiz [17]

You answer is: 17

Or otherwise B. is your correct answer.

(9 - 23) = -(14)

| 47 - 16| = 31

31 + (-14) = 17

5 0
3 years ago
How do you find the area of this composite figure?
Illusion [34]
If you notice the picture below

the composite figure is just a trapezoid sitting on top of a rectangle
and then, the rectangle has a triangular hole in it

so.. get the area of the trapezoid   \bf \textit{area of a trapezoid}=A=\cfrac{h}{2}(a+b)\qquad &#10;\begin{cases}&#10;h=height\\&#10;a,b=\textit{parallel sides or bases}&#10;\end{cases}

then get the area of the rectangle, which is just a 12x14
and then get the area of the triangle, which surely you know is 1/2 bh

then, subtract the triangle's area from the rectangle's area

and whatever is left, namely the difference, add that to the area of the trapezoid, and that's the composite's area

namely the area of the trapezoid plus the rectangle's, minus the triangle's

6 0
3 years ago
Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n

then the sequence solves the recurrence relation.

4 0
3 years ago
The sum of the first 15 terms of a geometric sequence with 7 as the first term and a common ratio of -3 is __________.
Andre45 [30]

Step-by-step explanation:

the formula for the sum of the first n terms of a geometric sequence is

Sn = s1(1 - r^n)/(1 - r)

with r being the common ratio and s1 is the first term.

so,

S15 = 7×(1 - (-3)¹⁵)/(1 - -3) = 7×(1 - -14,348,907)/4 =

= 7×14,348,908/4 = 7×3,587,227 = 25,110,589

4 0
2 years ago
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