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2 years ago

A vertex of a secant-tangent angle is a point on the circle. a. always c. never b. sometimes

1 answer:

4 0

Your answer is Sometimes because A secant passes through a circle at two points, a tangent at one.

Hope this helps :)
If you need more help in future let me know :D

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A chemist has a solution of 65% pure acid and another solution of 30% pure acid. How many gallons of each will make 350 gallons

AysviL [449]

Answer:

250 of 65% acid

100 gallons of 30% acid

Really sorry if this is incorrect, I had this question on my Lesson 16 test, and I don't know if it's correct or not...

8 0

2 years ago

Read 2 more answers

21. In 4 + In(4x - 15) = In(5x + 19)

Alexxx [7]

Answer:

$x=-30;\quad \:I\ne \:0$

Step-by-step explanation:

$In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)$

$\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\$

$\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\$

$\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:$

$\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0$

3 0

3 years ago

Select the correct answer.

Zigmanuir [339]

Answer:

E. 6

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find the value of x

fgiga [73]

$\qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star$

x = 35°

$\textsf{ \underline{\underline{Steps to solve the problem} }:}$

$\qquad❖ \: \sf \:4x + 1 + x + 4 = 180$

[ by linear pair ]

$\qquad❖ \: \sf \:5x + 5 = 180$

$\qquad❖ \: \sf \:5(x + 1) = 180$

$\qquad❖ \: \sf \:x + 1 = 180 \div 5$

$\qquad❖ \: \sf \:x + 1 = 36$

$\qquad❖ \: \sf \:x = 36 - 1$

$\qquad❖ \: \sf \:x = 35$

$\qquad \large \sf {Conclusion} :$

x = 35°

7 0

1 year ago

Why is the slope the same on a line when different points are used to identify the slope?

emmainna [20.7K]

Different points are used to identify the line, this can mean that both points lie on the same line.
Therefore the slope is the same because the line passes through both those points.

7 0

2 years ago