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Maslowich
2 years ago
9

I need help please 16x-20y=60 slope intercept form

Mathematics
1 answer:
nexus9112 [7]2 years ago
7 0
The slope intercept form is y=(4/5)x-(6/2)
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z 5 ​ − z+2 2z+4 ​ =−3 space, startfraction, 5, divided by, z, end fraction, minus, start fraction, 2, z, plus, 4, divided by, z
yan [13]

Answer:

The sum of all the possible values for z that satisfy the above equation is -5.

Step-by-step explanation:

The given equation is

\frac{5}{z}-\frac{2z+4}{z+2}=-3

We need to find the sum of all the possible values for z that satisfy the above equation.

The given equation can be rewritten as

\frac{5}{z}-\frac{2(z+2)}{z+2}=-3

Cancel out common factors.

\frac{5}{z}-2=-3

Add 2 on both sides.

\frac{5}{z}-2+2=-3+2

\frac{5}{z}=-1

5=-z

Multiply both sides by -1.

-5=z

Only z=-5 satisfy the given equation.

Therefore the sum of all the possible values for z that satisfy the above equation is -5.

8 0
3 years ago
How much cheaper per ounce is purchasing 7 ounces for $7.84 compared to purchasing 5 ounces for $5.70
WARRIOR [948]
7.84/7 = $1.12
5.70/5 = $1.14
1.14 - 1.12 = .2
2 cents cheaper
7 0
2 years ago
Evaluate each function at the given value using the Remainder Theorem.
belka [17]

Answer: C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the solution to the following equation?
Liono4ka [1.6K]

Answer: X-3(2x-8)= -25

A. X= 11

B. X= 14

C. X=10

D. x=5

Step-by-step explanation:

4 0
3 years ago
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
3 years ago
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