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alexandr1967 [171]

3 years ago

13

Helpppp!!! ASAP!!!!!!!!

2 answers:

Gala2k [10]3 years ago

5 0

Should be 0 becuase 600 -600 is 0

olga55 [171]3 years ago

3 0

It should be 0 hope it helps :)

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Consider two functions f and g on [1, 8] such that integral^8_1 f(x) dx = 9, integral^8_1 g(x) dx = 5, integral^8_5 f(x) dx = 4,

Gelneren [198K]

I'll abbreviate the definite integral with the notation,

$I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx$

We're given

$I(f,1,8)=9$
$I(g,1,8)=5$
$I(f,5,8)=4$
$I(g,1,5)=3$

Recall that the definite integral is additive on the interval $[a,b]$ , meaning for some $c\in[a,b]$ we have

$I(f,a,b)=I(f,a,c)+I(f,c,b)$

The definite integral is also linear in the sense that

$I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)$

for some constant scalars $k,\ell$ .

Also, if $a\ge b$ , then

$I(f,a,b)=-I(f,b,a)$

a. $I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}$

b. $I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}$

c. $I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}$

d. $I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}$

e. $I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}$

f. $I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}$

4 0

3 years ago

Plz help me the question is in the picture

Kobotan [32]

10.5 or 10 1/2 basically ten and a half

6 0

3 years ago

Classify ABC by its angles when mA = 26°, mB = 84°, and mC = 70°.

ryzh [129]

All of the angles would be acute angles because they are less then 90 degrees

4 0

3 years ago

Tyler is thinking of a number that is divisible by 2 and by 3. Write another number in which Tyler's number must also be divisib

Mumz [18]

Answer:

6

Step-by-step explanation:

6 because 6/2=3,6/3=2

3 0

3 years ago

(3x - 4)(4x2 - 5x + 6)

Oduvanchick [21]

That would be 12x^3-16x^2+3x-4

6 0

3 years ago