Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
Answer:
Range values are:
{-11, 1, 4, 10, 25}
Step-by-step explanation:
Domain values are the possible x values that can be entered into the function, or the inputs. Range values are the y values, or the outputs. By inserting every value in the set into the function, we get the outputs (y values)
-15 + 4 = -11
-3+4 = 1
0 + 4 = 4
6 + 4 = 10
21 + 4 = 25
Remember to put them in order.
