Ask question

Ask question

All categories

3 years ago

9

How to do geometry proofs I believe it's the subtraction property

1 answer:

notsponge [240]3 years ago

8 0

Hi there!
You need to prove that line segment DE ≅ GH.

You're given:
Line segment DJ ≅ line segment GJ;
E is the midpoint of line segment DF;
H is the midpoint of line segment GJ.

You can justify that line segment DE ≅ line segment GH with the midpoint definition, which is a point on a line segment that divides it into two equal parts. The two equal parts in this case are line segments DE and GH, so DE ≅ GH.

Please comment with <em></em>any questions!

You might be interested in

(x^3+10x^2+2)/(x+10)

SCORPION-xisa [38]

The quotient is x^2

The remainder is 2

Step-by-step explanation:

We need to divide: $\frac{\left(x^3+10x^2+2\right)}{x+10}$

The division is shown in figure attached.

The quotient is x^2

The remainder is 2

Keywords: Division of polynomials

Learn more about Division of polynomials at:

#learnwithBrainly

8 0

3 years ago

The perimeter of a rectangle is 30 inches. It’s area is 44 square inches. Find its length and width.

Verizon [17]

Answer:

length 11 width 4

Step-by-step explanation:

perimeter:

11+11=22

4+4=8

22+8=30

area:

11*4=44

4 0

2 years ago

Evaluate r +<br> Evaluate go when r = 14 and s = 8<br> when r = 14 and s = 8.

serious [3.7K]

Answer:

22

Step-by-step explanation:

thats the answer alright

5 0

4 years ago

What binomial do you have to add to the polynomial:

marshall27 [118]

Answer:

a) $-2x^2+5xy$

b) $-3y^2+5xy$

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

$-2x^2+5xy$

$(2x^2+3y^2-5xy+1)+(-2x^2+5xy)$

$=2x^2+3y^2-5xy+1-2x^2+5xy$

$=2x^2-2x^2+3y^2-5xy+5xy+1$

$=3y^2+1$

<u>Part (b)</u>

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

$-3y^2+5xy$

$(2x^2+3y^2-5xy+1)+(-3y^2+5xy)$

$=2x^2+3y^2-5xy+1-3y^2+5xy$

$=2x^2+3y^2-3y^2-5xy+5xy+1$

$=2x^2+1$

7 0

2 years ago

A histogram titled Number of texts has time on the x-axis and texts on the y-axis. From 6 a m to 8 a m there were 15 texts, 8 to

Varvara68 [4.7K]

Answer:

The cluster from 4 p.m.–10 p.m. means that most of the texts were sent in the afternoon and evening.

More texts were sent from 6 p.m.–8 p.m. than from 8 p.m.–10 p.m.

Step-by-step explanation:

From 6 a m to 8 a m there were 15 texts,

8 to10 a m: 5, 10 a m to 12 p m: 0,

12 p m to 2 p m: 0,

2 p m to 4 p m: 0,

4 to 6 p m: 29,

6 to 8 p m: 19,

8 to 9 p m, 14,

10 p m to 12 a m: 5.

3 0

3 years ago

Read 2 more answers