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3 years ago

24/25 is A. equal to B. less than C. greater than 96%

Mathematics

1 answer:

ale4655 [162]3 years ago

5 0

Answer:

<h2>A. equal to 96%</h2>

Step-by-step explanation:

$p\%=\dfrac{p}{100}$

$\dfrac{24}{25}=\dfrac{24\cdot4}{25\cdot4}=\dfrac{96}{100}=96\%$

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Suppose 56%of politicians are lawyers.If a random sample of size 564 is selected, what is the probability that the proportion of

IceJOKER [234]

Answer: 0.9444

Step-by-step explanation:

Given: The proportion of politicians are lawyers : <em>p </em>=0.56

Sample size : n = 564

Let q be th sample proportion.

The probability that the proportion of politicians who are lawyers will differ from the total politicians proportion by greater than 4% will be :-

$P(|q-p|$

Hence, the required probability = 0.9444

8 0

3 years ago

Find the missing measures for the rectangle. l = _?_ w = 4.2 m A = 37.8 m2 P = _?_ A) 9 m; 26.4 m B) 14.7 m; 61.74 m C) 9 m; 13.

egoroff_w [7]

Answer:

The correct answer is A.

Step-by-step explanation:

The area of a rectangle can be calculated using the following formula:

$Ar=W . I$

If we know that the area measures $37.8 m^{2}$ and one side of the figure measures 4.2 m, we can say that:

$37.8m^{2}=4.2m. I$

We isolate the side we don't know:

$\frac{37.8m^{2}}{4.2m} = I\\9 m = I$

So I = 9 m

To know the perimter of a rectangle, we use the following formula:

$P= I. 2 + W . 2$

$P= 9m. 2 + 4.2m. 2$

$P= 26.4 m$

3 0

3 years ago

The mean annual salary for intermediate level executives is about $74000 per year with a standard deviation of $2500. A random s

horrorfan [7]

Answer: D. 0.306

Step-by-step explanation:

Assuming a normal distribution for the annual salary for intermediate level executives, the formula for normal distribution is expressed as

z = (x - u)/s

Where

x = annual salary for intermediate level executives

u = mean annual salary

s = standard deviation

From the information given,

u = $74000

s = $2500

We want to find the probability that the mean annual salary of the sample is between $71000 and $73500. It is expressed as

P(71000 lesser than or equal to x lesser than or equal to 73500)

For x = 71000,

z = (71000 - 74000)/2500 = - 1.2

Looking at the normal distribution table, the probability corresponding to the z score is 0.1151

For x = 73500,

z = (73500 - 74000)/2500 = - 0.2

Looking at the normal distribution table, the probability corresponding to the z score is 0.4207

P(71000 lesser than or equal to x lesser than or equal to 73500) is

0.4207 - 0.1151 = 0.306

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3 years ago

What is 1 + 1<br> (first gets brainliest)

snow_tiger [21]

Answer:

Step-by-step explanation:

bet

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3 years ago

Find the critical points of the surface f(x, y) = x3 - 6xy + y3 and determine their nature.

Vedmedyk [2.9K]

Compute the gradient of $f$ .

$\nabla f(x,y) = \left\langle 3x^2 - 6y, -6x + 3y^2\right\rangle$

Set this equal to the zero vector and solve for the critical points.

$3x^2-6y = 0 \implies x^2 = 2y$

$-6x+3y^2=0 \implies y^2 = 2x \implies y = \pm\sqrt{2x}$

$\implies x^2 = \pm2\sqrt{2x}$

$\implies x^4 = 8x$

$\implies x^4 - 8x = 0$

$\implies x (x-2) (x^2 + 2x + 4) = 0$

$\implies x = 0 \text{ or } x-2 = 0 \text{ or } x^2 + 2x + 4 = 0$

$\implies x = 0 \text{ or } x = 2 \text{ or } (x+1)^2 + 3 = 0$

The last case has no real solution, so we can ignore it.

Now,

$x=0 \implies 0^2 = 2y \implies y=0$

$x=2 \implies 2^2 = 2y \implies y=2$

so we have two critical points (0, 0) and (2, 2).

Compute the Hessian matrix (i.e. Jacobian of the gradient).

$H(x,y) = \begin{bmatrix} 6x & -6 \\ -6 & 6y \end{bmatrix}$

Check the sign of the determinant of the Hessian at each of the critical points.

$\det H(0,0) = \begin{vmatrix} 0 & -6 \\ -6 & 0 \end{vmatrix} = -36 < 0$

which indicates a saddle point at (0, 0);

$\det H(2,2) = \begin{vmatrix} 12 & -6 \\ -6 & 12 \end{vmatrix} = 108 > 0$

We also have $f_{xx}(2,2) = 12 > 0$ , which together indicate a local minimum at (2, 2).

3 0

2 years ago

24/25 is A. equal to B. less than C. greater than 96%​

24/25 is A. equal to B. less than C. greater than 96%