The block most effectively keep a sprite from moving off the screen if if on edge, bounce. Hence option B is correct.
<h3>
What is screen?</h3>
Screen is defined as a portable or stationary object that offers shelter, acts as a partition, etc., and often consists of a covered frame. Screening is defined as the procedure of locating or choosing individuals from a community according to one or more selection criteria.
The block will kept more perfectly if one of the edge there is bounce so that the box will not fall from the sprite.
Thus, the block most effectively keep a sprite from moving off the screen if if on edge, bounce. Hence option B is correct.
To learn more about screen, refer to the link below:
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Answer: MDM softwares
Explanation:
Here MDM refers to mobile device management software which provides people with the facilities of updating, installing creating backup of various mobile devices within an organisation. Moreover these software's provides tools for proper monitoring and to report their usage across various independent mobile device users. MDM is often used or interconnected with the term BYOD(Bring your own device), whereby employees of an organisation bring their own mobile devices and they are being managed by a MDM software centrally.
Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:
Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.81 times.
In general, synchronous communication means you have to wait for the answer all the time. The programming logic is simpler, but the cost that you spend a lot of time waiting.
If the options are:
<span>a. The people communicating don't need to be online at the same time.
b. There is lag time in the communication.
c. The communication occurs in real time.
a is false, you do need to be online to receive the message
b is true, typically you continue only after an acknowledgement
c is true, you wait for acknowledgement that occurs in real time (not necessarily fast though)</span>
Answer:
#include <iostream>
using namespace std;
int main() {
int *ip_arr,n;//pointer name inp_arr and integer n to store the size.
cin>>n;//size.
for(int i=0;i<n;i++)
ip_arr[i]=-1;//assigning -1 to every element.
for(int i=0;i<n;i++)
{
cout<<ip_arr[i]<<" ";//printing every element.
}
return 0;
}
output:-
100
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1
Explanation:
I am taking input of size.You should enter 100 for 100 values which have value -1.
