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Aloiza [94]
4 years ago
8

Enter the value of 7.(2+18) -14​

Mathematics
2 answers:
Digiron [165]4 years ago
8 0
126
That’s the answer
ryzh [129]4 years ago
7 0

Answer:

we are going to use BODMAS

7.(2+18) -14

is also 7×(2+18) -14

since B representing bracket comes first,

we add the numbers in the bracket.

2+18=20

7×(20) -14

then M representing multiplication comes next do we multiply.

7×20=140

140-14=126

that's it!

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What are the coordinates
anzhelika [568]

Answer:

(1.5,1)

Step-by-step explanation:

I don't know how to explain. I used GeoGebra and I put the coordinate down and then made lines. Line AC and line BD. Then I put a point on where it intersects and it comes out to (1.5,1). You can also use distance formula, but that is more work.

5 0
3 years ago
Is 2/3×3/8 less than equal to or greater than 2/3
allochka39001 [22]

Answer:

2/3×3/8 < 2/3

Step-by-step explanation:

2/3×3/8 =1/4=0.25

2/3=0.666...

2/3 is larger

8 0
3 years ago
Find the length of side a in simplest radical form with a rational denominator.
Goshia [24]

Answer:

x = 5.5

Step-by-step explanation:

Using a trig ratio, you can use sin, which is opposite over hypotenuse. sin(30)\textdegree=\frac{x}{11}

Now, multiply both sides by 11

11\cdot sin(30)\textdegree=x

this simplifies to x = \frac{11}{2} or 5.5.

Since sin30 is \frac{\pi}{6} radians, it can be written as \frac{11\pi}{6}.

8 0
2 years ago
In regina, saskatchewan, the average mid-afternoon temperature in january is -12.6°C.The average mid afternoon temperature in ju
Andrews [41]

Finding the difference between the two temperatures, it is found that Regina is 38.7ºC degrees colder in January than in July.

----------------------------

  • The mid-afternoon temperature in January is of -12.6ºC.
  • In July, it is of 26.1ºC.
  • The difference of the temperatures is given by:

26.1 - (-12.6) = 26.1 + 12.6 = 38.7

From the difference of 38.7ºC, there are two interpretations:

  • Regina is 38.7ºC degrees colder in January than in July.
  • Regina is 38.7ºC degrees warmer in July than in January.

A similar problem is given at brainly.com/question/22136310

6 0
2 years ago
Write each sum or difference as a product with positive arguments -4(sin4x - sin2x) A) 8cos 3xsin x B) 8sin xsin 3x C) -8cos 3xs
pshichka [43]

Answer:

C) -8cos 3xsin x

Step-by-step explanation:

To express -4(sin4x - sin2x)  as a product, we use the formula sinA - sinB = 2cos[(A + B)/2]sin[(A - B)/2.

Comparing sin4x - sin2x with sinA - sinB, A = 4x and B = 2x.

Substituting these into the equation, we have

sin4x - sin2x = 2cos[(4x + 2x)/2]sin[(4x - 2x)/2

sin4x - sin2 x = 2cos[6x/2]sin[2x/2]

sin4x - sin2x = 2cos3xsinx

So, -4(sin4x - sin2x) = -4(2cos3xsinx) = -8cos3xsinx

So, -4(sin4x - sin2x) = -8cos3xsinx

Thus, the answer is C

5 0
3 years ago
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