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Dmitriy789 [7]
3 years ago
10

How do I do this. I don’t understand how to put the numbers in that formula or whatever the heck it is.

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

5

Step-by-step explanation:

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Suppose the population of a town was 40,000 on January 1, 2010 and was 50,000 on January 1, 2015. Let P(t) be the population of
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Answer:

Given,

The initial population ( on 2010 ) = 40,000,

Let r be the rate of increasing population per year,

Thus, the function that shows the population after t years,

P(x)=40000(1+r)^t

And, the population after 5 years ( on 2015 ) is,

P(5)=40000(1+r)^{5}

According to the question,

P(5) = 50,000,

\implies 40000(1+r)^5=50000

(1+r)^5=\frac{50000}{40000}=1.25

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So, the population is increasing the with rate of 0.04654,

And, the population after t years would be,

P(t)=40000(1+0.04654)^t

\implies 40000(1.04654)^t

Since, the exponential function is,

f(x) = ab^x

Hence, by comparing,

a = 40000,

b = 1.04654

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4 years ago
Without solving, what can you tell about the solution to
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