Answer:
x = 58/3
Step-by-step explanation:
We can use cross products to solve this problem
6 7
---------- = -----------
14 x-3
6 * (x-3) = 7 * 14
Divide each side by 6
6 /6* (x-3) = 7 * 14/6
x-3 = 98/6
Add 3 to each side
x-3+3 = 98/6 +3
x = 98/6 +18/6
x = 116/6
Divide the top and bottom by 2
x =58/3
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
36/10 is 36 divided by 10
So, you would divide 36 by 10 and as
36 = 36.000...
You would move the decimal place one place to the left.
3.6000... = 3.6
