0.193 ? 0.65A. <B. =C. >

Mathematics

1 answer:

Leviafan [203]3 years ago

4 0

Answer:

Step-by-step explanation:

The answer is A, reason why is because if you add a 0 to the end of the number 0.65, the problem would then say; 0.193 < 0.650. So, if you take off the 0. on the front of both decimals it would then say 193 < 650 and 650 is greater than 193.

You might be interested in

put the following equation of a line into slope-intercept form, simplifying all fractions 16x - 4y = -20

attashe74 [19]

Answer:

y = 4x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c

Given

16x - 4y = - 20 ( subtract 16x from both sides )

- 4y = - 16x - 20 ( divide terms by - 4 )

y = 4x + 5 ← in slope- intercept form

8 0

2 years ago

A quiz consists of 10 true or false questions. To pass the quiz a student must answer at least eight questions correctly.

lys-0071 [83]

Answer:

The probability of the student will pass the quiz = .0546

Step-by-step explanation:

Given -

Total no of question = 10

If the student guesses on each question there are two outcomes true of false

the probability of guesses question correctly = $\frac{1}{2}$

the probability of success is (p) = $\frac{1}{2}$

the probability of guesses question incorrectly = $\frac{1}{2}$

the probability of failure is (q) = 1- p = $\frac{1}{2}$

If the student guesses on each question he must answered at least 8 question correctly

the probability of the student will pass the quiz = $P(X\geq8 )$

= P(X = 8 ) + P(X = 9) + P(X = 10 )

= $\binom{10}{8}(p)^{8}(q)^{10 - 8} + \binom{10}{9}(p)^{9}(q)^{10 - 9} + \binom{10}{10}(p)^{10}(q)^{10 - 10}$

= $\frac{10!}{(2!)(8!)}(\frac{1}{2})^{8}(\frac{1}{2})^{10 - 8} +\frac{10!}{(1!)(9!)} (\frac{1}{2})^{9}(\frac{1}{2})^{10 - 9} + \frac{10!}{(0!)(10!)}(\frac{1}{2})^{10}(\frac{1}{2})^{10 - 10}$