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Gnesinka [82]
3 years ago
7

Maximize Q=xy^2, where x and y are positive numbers, such that x + y^2=10

Mathematics
1 answer:
mr Goodwill [35]3 years ago
8 0
X+y^2=10
minus x from both sides
y^2=10-x
sub (10-x) for y^2 in other equation
Q=x(10-x)
Q=10x-x^2
now find the maximum value
take the derititive
dQ/dx=10-2x
it is zero at x=5
below that, it is positive
after 5, it is negative
max at x=5

solve for y
y^2=10-x
y^2=10-5
y^2=5
sqrt both sides
y=√5



x=5
y=√5
the max value is 25
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Question 8 -
FinnZ [79.3K]

Answer:

Her wage on the 8th day is $105 ⇒ answer d

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- The average of set of data = The sum of data/the number of data

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∵ Cindy worked for 15 consecutive days

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∴ Her total earning = 91 × 15 = $1365

∵ Her average earning during the first 7 days is $87 per day

∴ Her total earning in the first 7 days = 87 × 7 = $609

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∵ Her total earning in the 14 days = 609 + 651 = $1260

∵ Her total earning in the 15 days is $1365

- To find her wage on the 8th day subtract her wage of the 14 days

  from her wage of the 15 days

∴ Her wage on the 8th day = 1365 - 1260 = $105

* Her wage on the 8th day is $105

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