We find the area of the total square which is 8in • 8in=64in^2 . Now we find the area of the small quadrilateral which is 4in•4in=16 in^2.
Now we subtract the area of the small quadrilateral from the big quadrilateral’s area 64in^2 -16in^2 leaving us with the are of 48in^2 of the figure
A) In Part 1 to part 2 the bus had its farthest distance. At part 2 the bus stayed steady time went by. Part 3 to 4 was decreasing distance. part 4 was constant. Then again at part 5 the distance was increasing
B)
1 - increasing
2 - constant
3 - decreasing
4 - constant
5 - increasing
C) Non-linear, because the graph has a curve, for it to be linear it must be a straight line.
Hope this Helps :)
Answer:
1c 2b
Step-by-step explanation:
Answer X = 2
Step-by-step explanation:
-30 + -18 - X + - 24,
+ 30 +30
0 6
-18 -x = -6
DIVIDE
3 -x = -1
BRING THE 3 OVER TO THE NEGATIVE ONE
YOU GET
X = 2
