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Alenkasestr [34]
4 years ago
9

Find the length of a diagonal of a rectangle ABCD with vertices A (-3, 1) B (-1, 3) C(3, -1) and D (1,-3)

Mathematics
2 answers:
Basile [38]4 years ago
8 0

The answer would be 6.3    


Novay_Z [31]4 years ago
4 0
The length of the diagonal may be determined by using the points A and C or B and D. Choosing A and C, the length of the diagonal is,
                             d = sqrt ((x₂ - x₁)² + (y₂ - y₁)²)
Substituting the known variables,
                             d = sqrt (3 - -3)² + (-1 - 1)²)
                                   d = sqrt 40
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The ratio 1331 : x is equivalent to the ratio <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3A%201331" id="TexFormula1" title
Marrrta [24]

Answer:

121

Step-by-step explanation:

Set up the equation 1331/x=x^2/1331

Cross multiply and simplify the answer.

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Need help click picture please!!
IrinaK [193]

Answer:

    = 37 cm^2

Step-by-step explanation:

To find the area of the figure, we will split it into 2 separate shapes.

We have a long skinny rectangle and a shorter wider rectangle.

The long skinny rectangle is 15 cm by 2 cm

The area is given by

A = l*w

A = 15*2 = 20 cm^2

The shorter wider rectangle is 7 cm by (3-2) cm  or 7 cm by 1 cm

The side length of the bottom rectangle is found by subtracting the length of the skinny rectangle from the total side length.

( The drawing is not to scale)

The area is given by

A = l*w

A = 7 * 1 = 7 cm^2

To find the area of the figure, we add up the area of the two rectangles

A total figure = rectangle 1 + rectangle 2

                     = 30 + 7

                      = 37 cm^2

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3 years ago
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