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Paraphin [41]
3 years ago
6

V/12 = 6/9 simplify and find v

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Answer:

8

Step-by-step explanation:

v/12 = 6/9

(v/12) * 12 = (6/9) * 12

v = 6(12)/9

v - 72/9

v=9

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Suppose the band is raising money to help offset the cost of a trip. You
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Answer:

y-step explanation:

8 0
3 years ago
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the graph shown below expresses a redical function that can be written in the form f(x)= a(x+k)^1/n + c. what does the graph tel
Oliga [24]

The value of n given the form of the function is (b) positive odd number

<h3>How to interpret the graph?</h3>

The form of the graph is given as:

f(x) = a(x + k)^1/n + c

For the given graph, we have the following features:

a > 0 --- a is positive

k > 0 --- k is positive

c < 0 --- c is negative

If n is an even number, the function would be undefined because the even root of a number is undefined

However, the function is defined if n is an odd number,

Hence, the value of n given the form of the function is a positive odd number

Read more about functions at:

brainly.com/question/4025726

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8 0
2 years ago
Name/ Uid:1. In this problem, try to write the equations of the given surface in the specified coordinates.(a) Write an equation
Gemiola [76]

To find:

(a) Equation for the sphere of radius 5 centered at the origin in cylindrical coordinates

(b) Equation for a cylinder of radius 1 centered at the origin and running parallel to the z-axis in spherical coordinates

Solution:

(a) The equation of a sphere with center at (a, b, c) & having a radius 'p' is given in cartesian coordinates as:

(x-a)^{2}+(y-b)^{2}+(z-c)^{2}=p^{2}

Here, it is given that the center of the sphere is at origin, i.e., at (0,0,0) & radius of the sphere is 5. That is, here we have,

a=b=c=0,p=5

That is, the equation of the sphere in cartesian coordinates is,

(x-0)^{2}+(y-0)^{2}+(z-0)^{2}=5^{2}

\Rightarrow x^{2}+y^{2}+z^{2}=25

Now, the cylindrical coordinate system is represented by (r, \theta,z)

The relation between cartesian and cylindrical coordinates is given by,

x=rcos\theta,y=rsin\theta,z=z

r^{2}=x^{2}+y^{2},tan\theta=\frac{y}{x},z=z

Thus, the obtained equation of the sphere in cartesian coordinates can be rewritten in cylindrical coordinates as,

r^{2}+z^{2}=25

This is the required equation of the given sphere in cylindrical coordinates.

(b) A cylinder is defined by the circle that gives the top and bottom faces or alternatively, the cross section, & it's axis. A cylinder running parallel to the z-axis has an axis that is parallel to the z-axis. The equation of such a cylinder is given by the equation of the circle of cross-section with the assumption that a point in 3 dimension lying on the cylinder has 'x' & 'y' values satisfying the equation of the circle & that 'z' can be any value.

That is, in cartesian coordinates, the equation of a cylinder running parallel to the z-axis having radius 'p' with center at (a, b) is given by,

(x-a)^{2}+(y-b)^{2}=p^{2}

Here, it is given that the center is at origin & radius is 1. That is, here, we have, a=b=0,p=1. Then the equation of the cylinder in cartesian coordinates is,

x^{2}+y^{2}=1

Now, the spherical coordinate system is represented by (\rho,\theta,\phi)

The relation between cartesian and spherical coordinates is given by,

x=\rho sin\phi cos\theta,y=\rho sin\phi sin\theta, z= \rho cos\phi

Thus, the equation of the cylinder can be rewritten in spherical coordinates as,

(\rho sin\phi cos\theta)^{2}+(\rho sin\phi sin\theta)^{2}=1

\Rightarrow \rho^{2} sin^{2}\phi cos^{2}\theta+\rho^{2} sin^{2}\phi sin^{2}\theta=1

\Rightarrow \rho^{2} sin^{2}\phi (cos^{2}\theta+sin^{2}\theta)=1

\Rightarrow \rho^{2} sin^{2}\phi=1 (As sin^{2}\theta+cos^{2}\theta=1)

Note that \rho represents the distance of a point from the origin, which is always positive. \phi represents the angle made by the line segment joining the point with z-axis. The range of \phi is given as 0\leq \phi\leq \pi. We know that in this range the sine function is positive. Thus, we can say that sin\phi is always positive.

Thus, we can square root both sides and only consider the positive root as,

\Rightarrow \rho sin\phi=1

This is the required equation of the cylinder in spherical coordinates.

Final answer:

(a) The equation of the given sphere in cylindrical coordinates is r^{2}+z^{2}=25

(b) The equation of the given cylinder in spherical coordinates is \rho sin\phi=1

7 0
3 years ago
Can someone please help I will give you 30 points and brainliest if the answer is right also no links please
Zolol [24]

Answer:

B: BC ≅EC

Step-by-step explanation:

You know that the two angles starting in C are congruent (they're opposite by vertex C).

Given that the B angle and the E angle are congruent, in order for the two triangles to be congruent by A(ngle)S(ide)A(ngle) you want the side inbetween to be congruent. That is BC and EC. Option B

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2 years ago
Write two expressions that could be
N76 [4]

Answer:$80.24

Step-by-step explanation:68*0.18(18%)

12.24

68+12.24=$80.24

3 0
2 years ago
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