Compare the quantities in Column A and Column B.
1 answer:
The y-intercept of and the y-intercept of
are equal
The equations are given as:
Make y the subject in both equations
<u>First equation</u>
<u>Second equation</u>
A linear equation is represented as:
Where b represents the y-intercept
So: By comparison,
--- the y-intercept of the first equation
--- the y-intercept of the second equation
2 = 2.
Hence, the y-intercept of and the y-intercept of
are equal
Read more about y-intercepts at:
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Answer:
The Fundamental Theorem of Algebra assures that any polynomial f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i
Step-by-step explanation:
1) This claim is mistaken.
2) The Fundamental Theorem of Algebra assures that any polynomial f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.
For example:
3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:
We'll have <em>n </em>different complex roots, not necessarily 2i.
For example:
Taking 3 polynomial equations with real coefficients, with
2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i