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3 years ago

Solve the inequality 2x < 6

Mathematics

1 answer:

Dima020 [189]3 years ago

8 0

Answer:

x < 3

Step-by-step explanation:

2x < 6

Divide each side by 2

2x/2 < 6/2

x < 3

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A box contains three cards. On one card there is a question mark (Upper Q), on another card there is a pear (Upper P), and o

vova2212 [387]

Complete question :

Determine the probability that two pears are selected The probability is(Simplity your answer.)

d) Determine the probability that a card containing a PEAR and then a card containing a question mark are selected

Answer:

(QQ, QP, QM, QP, PP, MP, QM, PM, MM) ;

Step-by-step explanation:

Given :

Marking on card :

Question mark = Q

Pear = P

Moon = M

Selecting two cards with replacement :

Sample space :

_____ Q ____ P _____ M

Q ___QQ ___QP ___ QM

P ___QP ____PP ___ MP

M__ QM ____PM ___MM

(QQ, QP, QM, QP, PP, MP, QM, PM, MM) ;

1/9 ;

2/9

P(selecting 2 pears) = (PP)

P(p) = required outcome / Total possible outcomes = 1 / 9

Card containing a pear and then a question mark ;

(PQ or QP).

P(p) = 1/3 ; P(Q) = 1/3

P(PQ) + P(QP)

(1/3 * 1/3) + (/3 * 1/3)

1/9 + 1/9

(1 + 1) / 9

= 2/9

6 0

3 years ago

Can someone answer this for me pls!

victus00 [196]

Answer:

Step-by-step explanation

let's William money be w

w=2*n=2n

so expression is

8 0

3 years ago

Read 2 more answers

It is possible to score higher than 1600 on the combined mathematics and reading portions of the SAT, but scores 1600 and above

Citrus2011 [14]

Answer:

The proportion of scores reported as 1600 is 0.0032

Step-by-step explanation:

Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).

In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)

$W = \frac{X-\mu}{\sigma} = \frac{X-1011}{216} \simeq N(0,1)$

The values of the cummulative distribution function of the standard Normal random variable, lets denote it $\phi$ are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600

$P(1600< X) = P(\frac{1600-1011}{216} < \frac{X-1011}{216}) = P(2.7269 < W) = 1- \phi(2.7269)\\= 1- 0.9968 = 0.0032$

Hence, the proportion of scores reported as 1600 is 0.0032.

Download pdf

5 0

4 years ago

A farm lets you pick 3 pints of raspberries for $12.00.

Aloiza [94]

Answer:a.4 dollars per pint

b.4th a pint/ 1 cup per dolllar

c. 5 pints

d.32 dollars

Step-by-step explanation:

6 0

3 years ago

Evaluate 4 E a=1 (n-1)

Fynjy0 [20]

4Ea =1

n-1

Hope this helps you buddy!:)

6 0

3 years ago