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3 years ago

Which polygons are congruent?

Mathematics

1 answer:

Liula [17]3 years ago

8 0

Answer:

the two rectangles that is labeled pqrs

the two trapazoids labeled lmno

the trapezoids labelded abcd

Step-by-step explanation:

i just took the keystone school test.

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A bottle of liquid cleaner contains 120 fluid ounces. If one wash load requires 4 ounces of the detergent, how many washes can

Trava [24]

Answer:

Step-by-step explanation:

120/4 = 30

Hope this helps

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3 years ago

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Natalija [7]

Answer:

The correct answer is A

Step-by-step explanation:

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2 years ago

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borishaifa [10]

X to the power of two+81

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2 years ago

What is the magnitude (size) of 6.8?

lidiya [134]

Answer:

C. 6.8, because |6.8|= 6.8

Step-by-step explanation:

The magnitude of a directed number is a property that turns the number to a positive of its value. Thus, the magnitude of a negative number equals its positive value. Examples:

Find the magnitude of the following numbers:

i. -20

ii. 10

iii. -5

iv. 2

The magnitudes of the numbers can be expressed as:

i. |-20| = 20

ii. |10| = 10

iii. |-5| = 5

iv. |2| = 2

Therefore, the magnitude of 6.8 = 6.8, because |6.8|= 6.8.

7 0

2 years ago

The owner of a bike shop that produces custom built bike frames has determined that the demand equation for bike frames is given

o-na [289]

Answer:

equilibrium point (10,340)

Step-by-step explanation:

To find the equilibrium point, equal the demand and the supply:

$D(q)=S(q)\\\\-6.10q^2-5q+1000=3.2q^2+10q-80$

Reorganize the terms in one side and reduce similar terms:

$3.2q^2+6.1q^2+5q+10q-80-1000=0\\\\9.3q^2+15q-1080=0$

that's a cuadratic equation, solve with the general formula when:

a=9.3, b=15, c=-1080

$q_{1}=\frac{-b+\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{1}=\frac{-15+\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{1}=\frac{-15+201}{18.6}\\\\q_{1}=\frac{186}{18.6}\\\\q_1=10$

q can't be negative because it is the quantity of bike frames, so:

$q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-15-\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{2}=\frac{-15-201}{18.6}\\\\q_{2}=\frac{-216}{18.6}\\\\$

This value of q can't be considered.

Then substitute the value of q in D(q) to find the price p:

$D(10) = -6.10(10)^2-5(10) + 1000\\\\D(10)=340=p$

The equilibrium point (q,p) is (10,340).

6 0

3 years ago