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monitta
2 years ago
5

ormula">
please help me how to solve this ​
Mathematics
1 answer:
sammy [17]2 years ago
6 0

Rewrite as ;

{:\implies \quad \sf (80+9)+(80+16)}

{:\implies \quad \sf (80+80)+(9+16)}

{:\implies \quad \sf 2(80)+(25)}

{:\implies \quad \sf 160+25}

{:\implies \quad \boxed{\bf 185}}

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A test taker gets 70 on 1st exam, 80 on 2nd exam, 2/3 of 4/5 of his 2nd exam on his 3rd test. If the professor gives 5 points ex
Serga [27]
<h3>Answer:  127</h3>

=================================================

Explanation:

The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.

The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.

Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.

So we have these scores

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  • second exam = 80
  • third exam = 43
  • fourth exam = x+5

Adding up these scores and dividing by 4 will get us the average

(sum of scores)/(number of scores) = average

(70+80+43+x+5)/4 = 80

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So the student got a score of x+5 = 122+5 = 127 on the fourth exam.

7 0
3 years ago
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