Answer:
Each student ticket costs $8.33
Each adult ticket costs $15.34
Step-by-step explanation:
At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?
s = cost of each student ticket
a = cost of adult ticket
Our system of equations:
4s + 2a = 64
3s + 3a = 71
-3(4s + 2a = 64) ==> -12s - 6a = -192
2(3s + 3a = 71) ==> 6s + 6a = 142
-12s - 6a = -192
6s + 6a = 142
-6s = -50
/-6 /-6
s = $8.33 (the cost of each student ticket)
Now, let's find the cost of each adult ticket:
4s + 2a = 64
4(8.33) + 2a = 64
33.32 + 2a = 64
-33.32 -33.32
2a = 30.68
/2 /2
a = 15.34 (the cost of each adult ticket)
(x, y) ==> (8.33, 15.34)
Check your answer:
4s + 2a = 64
4(8.33) + 2(15.34) = 64
33.32 + 30.68 = 64
64 = 64
This statement is true
Hope this helps!
The standard form of a quadratic equation is
,
where ,
, and
are coefficients. You want to get the given equation into this form. You can accomplish this by putting all the non-zero values on the left side on the equation.
In this case, the given equation is
Since is on the right side of the equation, we subtract that from both sides. The resulting equation is
Looking at the standard form equation , we can see that
Answer: The different possible solutions are 42, 21, 31 and 80.
Explanation:
The given expression is,
Case 1.
Case 2.
Case 3.
Case 4.